Java 、js list 排序

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Collections.sort(list, (o1, o2) -> Double.compare(o1.getDistance(), o2.getDistance()));

Collections.sort(listLevel,(o1,o2) -> {
    int a1=getSort(o1.getTitle());
    int a2=getSort(o2.getTitle());
    return a1-a2;
});

List<String> keys = new ArrayList<>(values.keySet());
Collections.sort(keys, String::compareTo);

 

js

data.sort(function (a, b) {
    return  b.value-a.value;
});

来源：oschina

链接：https://my.oschina.net/u/3677751/blog/3155410