Copy or move files to another directory based on partial names in a text file

问题

I want to copy some files from directory A to directory B on basis of partial filenames which are in a text file.

I tried the command below, but it's not working

for fn in $(cat filename.txt); do find . -type -f -name '$fn*' \
    -exec rsync -aR '{}' /tmp/test2 \;

File names are in format abcd-1234-opi.txt, rety-4567-yuui.txt. I have to grep numbers from file names and then copy those files to another folder, I have numbers in a text file.

Can anybody guide me?

回答1:

If I understand your question correct:

for file in $(<./example); do cp "${file}" /tmp/test2/; done

for file in $(<./example); do find . -type f -name ${file} -exec rsync -aR {} /tmp/test2/ \; ; done

回答2:

If understand correctly, the pattern to search for is the first 3 digits of the numbers after the first -, like this:

abd-12312-xyz
    ^^^

88-45644-oio
   ^^^

qwe-78908-678
    ^^^

Here's one way to write that:

while read line; do
    pattern=${line#*-}
    pattern=${pattern:0:3}
    find . -type f -name "*$pattern*" -exec rsync -aR {} /tmp/test2 \;
done < patterns.txt

If your inputs are like "veeram_20171004-104805_APOLLO_9004060859-all.txt", and you want to extract the "9004060859", then you can try to find a different logic to extract that. For example, "cut off every after the last '-', and everything before the last '_'". You can write like this:

pattern=${line%-*}
pattern=${pattern##*_}

回答3:

Running find repeatedly should probably be avoided. Instead, factor the expressions into the find command line programmatically.

awk 'BEGIN { printf "find . -type -f \\("; sep="" }
   { printf "%s -name \047*%s*\047", sep, $0; sep=" -o" }
   END { printf " \\) -exec rsync -aR '{}' /tmp/test2 \\;\n" }' filename.txt |
sh

Leave off the pipe to sh to test.

来源：https://stackoverflow.com/questions/47462385/copy-or-move-files-to-another-directory-based-on-partial-names-in-a-text-file

标签

Linux

bash

shell

command-line

scripting