Output isn't shown per line

问题

I wrote a simple python script like this:

#!/usr/bin/python
import sys
import urllib

if len(sys.argv) < 2:
        print 'usage: python %s <file-urls>' % (sys.argv[0])
        sys.exit(2)

print '%-15s %15s' % ('URL_PAGE', 'STATUS')

FileName = sys.argv[1]
InputFile = open(FileName)
for url in InputFile:
    out = urllib.urlopen(url)
    status = out.getcode()
    print '%-15s %15s' % (url, status)

The out put is something like this:

URL_PAGE                 STATUS
http://test.com
             200

But I want this output:

URL_PAGE                 STATUS
http://test.com           200

回答1:

strip the newline character (and useless whitespace) from url:

print '%-15s %15s' % (url.strip(), status)

来源：https://stackoverflow.com/questions/24467134/output-isnt-shown-per-line