问题
I want convert this text:
qa-ops01.mysite.com
/dev/mapper/sys-home 58G 26G 30G 47% /home
/dev/mapper/sys-tmp 3.9G 2.3G 1.5G 61% /tmp
qa-ops02.mysite.com
/dev/mapper/sys-home 58G 26G 30G 47% /usr
/dev/mapper/sys-tmp 3.9G 2.3G 1.5G 61% /var
qa-ops03.mysite.com
/dev/mapper/sys-home 58G 26G 30G 47% /lib
/dev/mapper/sys-tmp 3.9G 2.3G 1.5G 61% /etc
to this one:
qa-ops01.mysite.com /dev/mapper/sys-home 58G 26G 30G 47% /home
qa-ops01.mysite.com /dev/mapper/sys-tmp 3.9G 2.3G 1.5G 61% /tmp
qa-ops02.mysite.com /dev/mapper/sys-home 58G 26G 30G 47% /usr
qa-ops02.mysite.com /dev/mapper/sys-tmp 3.9G 2.3G 1.5G 61% /var
qa-ops03.mysite.com /dev/mapper/sys-home 58G 26G 30G 47% /lib
qa-ops03.mysite.com /dev/mapper/sys-tmp 3.9G 2.3G 1.5G 61% /etc
I have used
cat FILE |sed 'N;s/.com\n//'
Is there anyway to achieve this, or should I just write the If... Then...
Thanks everybody for the answers :D (you always show me new things :D)
回答1:
The answer by potong is almost correct; it only handles one server, rather than multiple servers, but the change required is small.
$ sed -e '/^[^ ]*$/{h;d;}' -e 'G; s/\(.*\)\n\(.*\)/\2 \1/' data
qa-ops01.mysite.com /dev/mapper/sys-home 58G 26G 30G 47% /home
qa-ops01.mysite.com /dev/mapper/sys-tmp 3.9G 2.3G 1.5G 61% /tmp
qa-ops02.mysite.com /dev/mapper/sys-home 58G 26G 30G 47% /usr
qa-ops02.mysite.com /dev/mapper/sys-tmp 3.9G 2.3G 1.5G 61% /var
qa-ops03.mysite.com /dev/mapper/sys-home 58G 26G 30G 47% /lib
qa-ops03.mysite.com /dev/mapper/sys-tmp 3.9G 2.3G 1.5G 61% /etc
$
The script is in two parts, identified by the two -e options. The first part identifies server names; those lines contain no spaces (hence /^[^ ]*$/ looks for a line with no spaces), and copies the line into the hold space (h) and then deletes it (d) and continues with the next line. The second part of the script is only exercised on lines that contain spaces. It appends the content of the hold space to the pattern space after a newline (G); then it splits the line into 'everything up to the newline' and 'everything after the newline', and switches them so that the 'after' (\2) comes first, then a space, then the 'before' (\1).
This uses the classic sed regular expressions; it was tested on Mac OS X (10.7.5) with both the BSD sed and also with GNU sed without change. GNU sed has options such as -r to change the interpretation of regexes which would save you a few backslashes.
回答2:
I don't know much about sed, but in AWK:
awk 'NR==1{prefix=$0;next} {print prefix, $0}' file
Update
If that is the case, look for lines with only one field (column), use it for prefix. That means, the only change to the above script is NF (number of fields) in place of NR (number of records, or lines).
awk 'NF==1{prefix=$0;next} {print prefix, $0}' file
回答3:
This might work for you (GNU sed):
sed -r '1{h;d};G;s/(.*)\n(.*)/\2 \1/' file
1{h;d}save the first line in the hold space (HS) and then delete the pattern space (PS).Gon all subsequent lines append a newline and the HS to PS.s/(.*)\n(.*)/\2 \1/re-arrange the PS and remove the introduced newline.
Since posting the answer the original question was changed, to take this into account:
sed -r '/%/!{h;d};G;s/(.*)\n(.*)/\2 \1/' file
This handles multiple servers by saving lines in the HS which do not contain %.
回答4:
try this one:
awk '!/^\/dev/{header=$0;next} {print header, $0}' input.txt
alternatively (functionally identical, but a bit easier to read and understand, IMO):
awk '{if($0 !~ /^\/dev/){header=$0}else{print header, $0}}' input.txt
回答5:
awk '{if($0~/mysite.com/){x=$0}else{print x,$0}}' your_file
tested here
回答6:
Another way using awk is as follows:
awk '{if ($1 ~ /mysite.com/){a= $0 } if ($1 ~ /dev/){ print a" "$0}}' temp.txt
a = $0copies the line to a if that containsmysite.com- If second lines contains
/devthen it joins both lines
or other variation of potong sed
sed -re '/mysite.com/{h;d};G;s/(.*)\n(.*)/\2 \1/' temp.txt
来源：https://stackoverflow.com/questions/14483341/bash-to-merge-lines-in-a-file