问题
I've a list of point with coordinates and another point.
A sample from the list :
(45.1531912,5.7184742),(45.1531912,5.7184742),(45.1531113,5.7184544),(45.1525337,5.718298),(45.1525337,5.718298),
A point :
(45.1533837,5.7185242)
A function :
def dist(point1,point2)
....
return aDistance
Is there a python one liner (list-comprehension ?) to find a point in the list where a given function returns the minimal value for the list ?
回答1:
The min() function takes a key argument already, no need for a list comprehension.
Let's say you wanted to find the closest point in the list to the origin:
min(list_of_points, key=lambda p: distance(p, (0, 0)))
would find it (given a distance() function that calculates the distance between two points).
From the documentation:
The optional key argument specifies a one-argument ordering function like that used for
list.sort(). The key argument, if supplied, must be in keyword form (for example,min(a,b,c,key=func)).
来源:https://stackoverflow.com/questions/22744237/python-finding-an-item-in-a-list-where-a-function-return-a-minimum-value