RxJS observe an object | 易学教程

问题

I am new to RxJS so I apologize for the newbie question.

I have a local javascript object defined as:

model.user = {
  firstName: 'John',
  lastName: 'Smith'
}

I am binding each property to an input control where the user can change the values. I would like to be able to observe this object and capture the event when the value of any of the properties change.

Is this achievable with RxJS?

Thanks.

回答1:

Instead of using an object, you can store your entire state as Observable.

Here is the example code (something similar to what people do in redux):

var fnameInput = document.getElementById('fname');
var lnameInput = document.getElementById('lname');
var jsonPre = document.getElementById('json');

var onFirstName$ = Rx.Observable.fromEvent(fnameInput, 'input');
var onLastName$ = Rx.Observable.fromEvent(lnameInput, 'input');

var initialState = {
  firstName: '', 
  lastName: '',
};

var state$ = Rx.Observable
  .merge(
    onFirstName$
      .map(e => 
        state => Object.assign(
          state, 
          { firstName: e.target.value }
        )
      ),
    onLastName$
      .map(e => 
        state => Object.assign(
          state, 
          { lastName: e.target.value }
        )
      )
  )
  .scan(
    (state, makeNew) => makeNew(state), 
    initialState
  )
  .startWith(initialState);

state$
  .subscribe(state => {
    jsonPre.innerHTML = JSON.stringify(state, null, 2);
  });

<input id="fname" type="text">
<input id="lname" type="text">
<pre id="json"></pre>

<script src="https://cdnjs.cloudflare.com/ajax/libs/rxjs/4.0.6/rx.all.js"></script>

来源：https://stackoverflow.com/questions/41268671/rxjs-observe-an-object

标签

rxjs