Infer a type of a tree in a scala macro

问题

Inside a macro, how can I ask the compiler to infer the type of a constructed tree? I've only found Context.typeCheck, but that only checks the types but doesn't return the result.

回答1:

If you've type-checked the tree you can just use its tpe method:

scala> def impl(c: Context) = c.literal(c.typeCheck(c parse "1+1").tpe.toString)
impl: (c: scala.reflect.macros.Context)c.Expr[String]

scala> def mac = macro impl
mac: String

scala> println(mac)
Int(2)

You could also wrap it in an expression, of course, but there's no need to if you just want the type.

回答2:

I figured it out and I hope this saves somebody else the hassle

import reflect.macros.Context
import language.experimental.macros

def impl(c: Context) = {
  val tree = c.parse("1+1")
  val expr = c.Expr[Any](c.typeCheck(tree))
  println(expr.staticType)
  println(expr.actualType)
  c.literalUnit
}

def mac = macro impl

By wrapping into Expr you get the ability to query for the actual type. Any is there to provide a legal upper bound. Without that the infered type would be Expr[Nothing] and you would be in trouble. The catch is to wrap the tree returned from c.typeCheck otherwise the Type is just null.

Method mac just returns () bu it prints out Any-upper bound and Int(2) -the actual type.

来源：https://stackoverflow.com/questions/17394389/infer-a-type-of-a-tree-in-a-scala-macro