问题
- Why does
Foo.valreturnnilinstead of"foo"before callingFoo.set? - Is there any mechanism for initializing
@valon class evaluation? In which scope is
@val = "foo"stored into?class Foo class << self @val = "foo" attr_reader :val def set(val) @val = val end end end p Foo.val # nil Foo.set("bar") p Foo.val # "bar"
回答1:
You can initialize @val in Foo like this:
class Foo
@val = "foo"
class << self
attr_reader :val
def set(val)
@val = val
end
end
end
p Foo.val #=> "foo"
Foo.set("bar")
p Foo.val #=> "bar"
Your code initializes @val not on Foo, but on Foo's metaclass
回答2:
Ruby generally executes expressions upon parsing them. The reason why your code did not perform as expected is because you are setting a class instance variable for the singleton class of Foo, but on the other hand you are accessing the class instance variable of Foo itself, that's why it doesn't work:
class << self
@val = "foo" # scope is class scope of singleton class of Foo
attr_reader :val
def set(val)
# scope is instance scope of singleton class of Foo (equal to Foo itself)
@val = val
end
end
That's why Foo.val yields nil in your case - it hasn't been set yet.
Setting val on class evaluation can be achieved in the way that Victor already demonstrated.
See also this post for a discussion about scope.
回答3:
No need to use #set. Simply define #val method and use nil guard:
class Foo
class << self
def val; @val ||= "bar" end
end
end
p Foo.val #=> "bar"
来源:https://stackoverflow.com/questions/6968333/ruby-metaprogramming-initialize-singleton-class-variable