Randomly initialize BitSet in JAVA

问题

I have BitSet which has to be initialized randomly. Is there any method to do that?

Thanks in advance.

回答1:

Just go through BitSet and call nextBoolean() of the Random class.

回答2:

If you are using Java 7, you can initialize a random byte array with Random.nextBytes(byte[]) then use the static BitSet.valueOf(byte[]) method to create a BitSet from the same byte array.

Random rnd = new Random();
// ...
byte[] randomBytes = new byte[NUM_BYTES];
rnd.nextBytes(randomBytes);
return BitSet.valueOf(randomBytes);

Or if you want the proportion of 0 vs. 1 bits to be something other than 50:50, check out an old SO question of mine.

回答3:

There is no such constructor. What you'd have to do is create a BitSet and then in a loop set all bits to random values.

来源：https://stackoverflow.com/questions/8557857/randomly-initialize-bitset-in-java