Paging stdout output in IPython

问题

Is it possible in an (interactive) IPython session to pass the stdout output through a pager, like less? If so, how?

For example, in

In [1]: from some_module import function_that_prints_a_lot

In [2]: function_that_prints_a_lot()

... everything scrolls away ...

I would like to page through the stdout output of function_that_prints_a_lot.

Another example:

In [1]: %run script_that_prints_a_lot.py

I've looked through IPython magic commands but didn't find any solution.

回答1:

As discussed in chat there is no simple way of doing this. Since the function prints the values, the only thing you can do is Capture output + Then page output. There are few issues on jupyter that you might be interested in

https://github.com/jupyter/notebook/issues/2049

https://github.com/ipython/ipython/issues/6516

Capturing output

Output capturing can be done multiple ways

1. Overload Print Method

import sys
data = ""
def myprint(value, *args, sep=' ', end='\n', file=sys.stdout, flush=False):
    global data
    current_text = value + " ".join(map(str, args)) + "\n"
    data += current_text

original_print = print
print = myprint

def testing():
    for i in range(1,1000):
        print ("i =", i)

testing()

original_print("The output from testing function is", data)

2. Capture output using StringIO

from cStringIO import StringIO
import sys

class Capturing(list):
    def __enter__(self):
        self._stdout = sys.stdout
        sys.stdout = self._stringio = StringIO()
        return self
    def __exit__(self, *args):
        self.extend(self._stringio.getvalue().splitlines())
        del self._stringio    # free up some memory
        sys.stdout = self._stdout

Usage:

with Capturing() as output:
    do_something(my_object)

3. Capture output using redirect_stdout

import io
from contextlib import redirect_stdout

f = io.StringIO()
with redirect_stdout(f):
    do_something(my_object)
out = f.getvalue()

4. Capture using %%capture magic command

Paging Output

You can use magin %page

%page -r <variablename>

https://ipython.readthedocs.io/en/stable/interactive/magics.html#magic-page

Or you can use Ipython code

from IPython.core import page
page.page(variable)

For more details refer to below

PS: Some helpful threads

How to capture stdout output from a Python function call?

How can I redirect print output of a function in python

https://github.com/ipython/ipython/wiki/Cookbook:-Sending-built-in-help-to-the-pager

overload print python

回答2:

Using bits and pieces from various sources, but essentially it's from IPython's cookbook and Defining custom magics from IPython official documentation

In [1]: from IPython.core.magic import register_line_magic

In [2]: @register_line_magic
   ...: def my_pager(line):
   ...:     "my line magic"
   ...:     import io
   ...:     from IPython.core import page
   ...:     from contextlib import redirect_stdout
   ...:     f = io.StringIO()
   ...:     with redirect_stdout(f):
   ...:         eval(line)
   ...:     page.pager_page(f.getvalue())
   ...: del my_pager # don't pollute my namespace    

In [3]: def pippo(): print('\n'.join(str(i)for i in range(80)))

In [4]: %my_pager pippo()

This approach has a serious drawback: if the function call that is the argument to %my_pager returns a value, said value is lost (no, %mypager result=print_and_return() won't work...)

来源：https://stackoverflow.com/questions/46951127/paging-stdout-output-in-ipython

标签

ipython

stdout