How to get a float result by dividing two integer values using T-SQL?

问题

Using T-SQL and Microsoft SQL Server I would like to specify the number of decimal digits when I do a division between 2 integer numbers like:

select 1/3

That currently returns 0. I would like it to return 0,33.

Something like:

select round(1/3, -2)

But that doesn\'t work. How can I achieve the desired result?

回答1:

The suggestions from stb and xiowl are fine if you're looking for a constant. If you need to use existing fields or parameters which are integers, you can cast them to be floats first:

SELECT CAST(1 AS float) / CAST(3 AS float)

SELECT CAST(MyIntField1 AS float) / CAST(MyIntField2 AS float)

回答2:

Because SQL Server performs integer division. Try this:

select 1 * 1.0 / 3

This is helpful when you pass integers as params.

select x * 1.0 / y

回答3:

It's not necessary to cast both of them. Result datatype for a division is always the one with the higher data type precedence. Thus the solution must be:

SELECT CAST(1 AS float) / 3

SELECT 1 / CAST(3 AS float)

回答4:

use

select 1/3.0

This will do the job.

回答5:

Might be a little late, but realize that CASTing to FLOAT is not allowed in MySQL and will raise an error when you attempt to CAST(1 AS float) as stated at MySQL dev.

The workaround to this is a simple. Just do

(1 + 0.0)

Then use ROUND to achieve a specific number of decimal places like

ROUND((1+0.0)/(2+0.0), 3)

The above SQL divides 1 by 2 and returns a float to 3 decimal places, as in it would be 0.500.

One can CAST to the following types: binary, char, date, datetime, decimal, json, nchar, signed, time, and unsigned.

回答6:

Looks like this trick works in SQL Server and is shorter (based in previous answers)

SELECT 1.0*MyInt1/MyInt2

Or:

SELECT (1.0*MyInt1)/MyInt2

回答7:

Use this

select cast((1*1.00)/3 AS DECIMAL(16,2)) as Result

Here in this sql first convert to float or multiply by 1.00 .Which output will be a float number.Here i consider 2 decimal places. You can choose what you need.