问题
How can I pass data from a controller after it performs certain action to a view through a redirect()
if I have a get route for it?
The logic of the app is to redirect with an user_id
to a view where the user will select its username after successfully verified its email.
public function confirm($confirmationCode){
if(!$confirmationCode){
dd('No se encontró ningún código de verificación en la URL');
}
$user = User::where('confirmation_code', $confirmationCode)->first();
if(!$user){
dd('Lo sentimos. Este código de confirmación ya ha sido usado.');
}
$user->confirmed = 1;
$user->confirmation_code = null;
$user_id = $user->user_id;
$user->save();
return redirect('assign-username')->with(compact('user_id'));
}
The get route:
Route::get('assign-username', 'AuthenticationController@showAssignUsernameForm');
And the code for the post request of the assign-user
form.
public function assignUsername(){
$user_id = request()->input('user_id');
$username = request()->input('username');
if(User::where('username', '=', $username)->exists()){
return redirect()->back()->withInput()->withErrors([
'username' => 'Este usuario ya se encuentra registrado. Intenta nuevamente'
]);
}else{
DB::table('user')->where('user_id', $user_id)->update(['username' => $username]);
}
}
When trying to access to the $user_id
variable it says it is not defined.
The view's code:
@extends('layouts.master')
@section('content')
<section class="hero">
<h1><span>Ya estás casi listo.</span>Es hora de seleccionar tu nombre de usuario</h1>
<div class="form-group">
<form class="form-group" method="post" action="assign-username">
{!! csrf_field() !!}
@if($errors->has('username'))
<span class="help-block" style="color:red">
<strong>{{ $errors->first('username') }}</strong>
</span>
@endif
<input type="hidden" name="user_id" value="{{ session('user_id') }}">
<input type="text" name="username" placeholder="Escribe tu nombre de usuario">
<button type="submit" class="btn" name="send">Registrar</button>
</form>
</div>
</section>
@endsection
Laravel Version: 5.2
回答1:
...
Update
Storing $user_id
on a hidden input is a bit risky, how if your user know how to change the value on browser such as Chrome developer console and replace it with another user id?
Rather than storing it on hidden input I would store it as session flash data, it could be:
public function confirm($confirmationCode){
....
session()->flash('user_id', $user_id); // Store it as flash data.
return redirect('assign-username');
}
On AuthenticationController@showAssignUsernameForm
tell Laravel to keep your user_id
for next request:
public function showAssignUsernameForm() {
session()->keep(['user_id']);
// or
// session()->reflash();
return view('your-view-template');
}
And on your assign username POST
method you can define the value like this:
public function assignUsername(){
$user_id = session()->get('user_id');
$username = request()->input('username');
if(User::where('username', '=', $username)->exists()) {
session()->flash('user_id', $user_id); // Store it again.
return redirect()->back()->withInput()->withErrors([
'username' => 'Este usuario ya se encuentra registrado. Intenta nuevamente'
]);
} else {
DB::table('user')->where('user_id', $user_id)->update(['username' => $username]);
}
}
回答2:
This should work:
public function assignUsername(Request $request)
{
$user_id = $request->user_id;
回答3:
If you're passing data to the view, to get the information after with(compact('user_id'))
you must do through Session
like this:
@if (session('user_id'))
<input type="hidden" name="user_id" value="{{ session('user_id') }}">
@endif
来源:https://stackoverflow.com/questions/37485527/how-to-pass-data-through-a-redirect-to-a-view-in-laravel