问题
I'm mapping a raw Stream to a Stream<Integer> and then collect the elements to a List<Integer>.
Why do I have to cast the result of collect(Collectors.toList()) to List<Integer> if my mapper - .map(str -> ((String)str).length()) - already maps to Integer?
My code:
List list = Arrays.asList("test", "test2");
List<Integer> lengths = (List<Integer>) list.stream()
.map(str -> ((String)str).length())
.collect(Collectors.toList());
If I don't use a raw List, there's no need to cast:
List<String> list = Arrays.asList("test", "test2");
List<Integer> lengths = list.stream()
.map(str -> str.length())
.collect(Collectors.toList());
回答1:
Calling list.stream() on a raw List produces a raw Stream. calling map on that Stream doesn't change that Stream to a generic Stream<Integer>. It changes it to another raw Stream. Therefore when you call collect(Collectors.toList()), you get a raw List and have to cast it to (List<Integer>).
Conclusion : don't use raw types.
来源:https://stackoverflow.com/questions/45054145/why-do-we-have-to-cast-the-list-returned-by-collectors-tolist-to-listinteger