问题
I'm using lineinfile as follows:
lineinfile dest=./hosts_exp insertafter='\[hosts1\]' line="xxxxxxxxx" state=present
My hosts_exp is as follows:
[local]
localhost
[hosts1]
[hosts2]
[hosts3]
lineinfile inserts the text after [hosts3] instead of inserting it after [hosts1].
回答1:
use:
lineinfile:
dest: "./hosts_exp"
line: "xxxxxxxxx"
insertafter: '^\[hosts1\]'
state: present
回答2:
example:
- name: "blah"
lineinfile:
dest: "/test.sh"
insertafter: 'test text'
line: "text add"
state: present
回答3:
It appears redundant, but you need to specify the regex too:
lineinfile:
dest: ./hosts_exp
insertafter: '\[hosts1\]'
regexp: '\[hosts1\]'
line: "xxxxxxxxx"
state=present
Why? The regexp says "look for this line". The insertafter says "inject the line here".
I tested this; here's the commit. There are a few minor changes in my commit from the line above, use as necessary.
回答4:
Use backrefs: yes
lineinfile:
backrefs: yes
dest: ./hosts_exp
insertafter: '\[hosts1\]'
regexp: '\[hosts1\]'
line: "xxxxxxxxx"
state=present
This flag changes the operation of the module slightly; insertbefore and insertafter will be ignored, and if the regexp doesn't match anywhere in the file, the file will be left unchanged. If the regexp does match, the last matching line will be replaced by the expanded line parameter.
来源：https://stackoverflow.com/questions/24173114/ansible-lineinfile-insertafter-injects-line-at-end-of-file