Get a Haskell record's field names as a list of strings?

问题

Say I have the following:

data Rec = Rec {
    alpha :: Int,
    beta  :: Double,
    phi   :: Float 
} 

sample = Rec 1 2.3 4.5

I understand Template Haskell & the reify function can get me the record's field names. That is:

print $(f sample) --> ["alpha", "beta", "phi"]

There is also a claim that this can be done without Template Haskell. Can someone provide an example implementation for this can be accomplished?

回答1:

It can be done with a Data (most GHC versions) or Generic (7.2.x and up) instance, which GHC can derive for you. Here's an example of how to dump record fields with the Data typeclass:

{-# LANGUAGE DeriveDataTypeable #-}

import Data.Data

data Rec = Rec {
    alpha :: Int,
    beta  :: Double,
    phi   :: Float 
}  deriving (Data, Typeable)

sample = Rec 1 2.3 4.5

main :: IO ()
main = print . constrFields . toConstr $ sample 

来源：https://stackoverflow.com/questions/8457876/get-a-haskell-records-field-names-as-a-list-of-strings