问题
I have a basic model named "Places" which has this view:
def view_index(request, place_name):
The user will access that view with a URL like this one:
http://server.com/kansas
"kansas" is a value stored in a field named "name" inside the model "Places".
The problem is that I can't figure out how to obtain the object id based just on the object name. Is there a way to do this?
回答1:
Like this:
place = Places.objects.get(name='kansas')
print place.id
回答2:
Since you only want id, you should only query for id. A naive get will retrieve all fields on the database row. Either of these methods will only retrieve the data you want.
id = Place.objects.filter(name='kansas').values('id')[0]['id']
Or with values_list:
id = Place.objects.filter(name='kansas').values_list('id', flat=True).first()
Another method uses only:
id = Place.objects.only('id').get(name='kansas').id
回答3:
What does your URL mapping for that view look like? Assuming you're capturing the part of your URL with "kansas" in it and that is getting set to the place_name argument, you'll have to do a simple filter on your model's manager on whatever model field you're looking for "kansas" in.
If your URL mapping looks like:
('(?P<place_name>\w+)$', 'myapp.view.view_index')
Then you should be able to do just
object_list = Model.objects.filter(place_name = place_name)
to get a list of objects who have a place_name that matches the one in the URL. From there, each of the objects in that list should have an id (unless you've renamed the ID field) that you can get to like any other python object attribute.
来源：https://stackoverflow.com/questions/4659360/get-django-object-id-based-on-model-attribute