How to disable render view in zend framework 2?

问题

I want to use some ajax, but I don't know how to use function as the same as setNoRender() in zend framework 2 to disable for render view.

How to disable rendering view in zend framework 2?

回答1:

To disable your view :

public function myactionAction()
{
    // your code here ...
    return false;
}

"return false" disables the view and not the layout! why? because the accepted types are:

ViewModel
array
null

so "false" disable the view.

To disable layout and view, return a response object:

public function myactionAction()
{
    // your code here ...
    return $this->response;
}

To disable layout:

public function myactionAction()
{
    // your code here ...
    $view = new ViewModel();
    $view->setTerminal(true);
    return $view;
}

回答2:

If you're using JSON, then look at the view's JsonStrategy and return a JsonModel from you controller. See this article.

Alternatively, you can return an Response from your controller and the whole view layer is skipped:

public function testAction()
{
    $response = $this->getResponse();
    $response->setStatusCode(200);
    $response->setContent('foo');
    return $response;
}

回答3:

Proper and simple solution to do this

public function testAction()
{
    $data = array(
        'result' => true,
        'data' => array()
    );
    return $this->getResponse()->setContent(Json::encode($data));
}

Details: http://cmyker.blogspot.com/2012/11/zend-framework-2-ajax-return-json.html

回答4:

I found some answer.

Though $this->layout()->getLayout() returns the name/path of the newly selected layout... The layout does not change with any of the following commands...

within a controller

$this->getLocator()->get('view')->layout()->setLayout('layouts/ajax.phtml');
$this->getLocator()->get('view')->layout()->setLayout('ajax');
$this->getLocator()->get('view')->layout()->disableLayout();

within a view PHTML file

$this->layout()->setLayout('layouts/ajax.phtml');
$this->layout()->setLayout('ajax');
$this->layout()->disableLayout();

回答5:

$view = new ViewModel(); $view->setTerminate(true);

回答6:

...
use Zend\View\Model\JsonModel;

public function myAction() {
    ...

    $view = new JsonModel($myArray);
    $view->setTerminal(true);
    return $view;
}

来源：https://stackoverflow.com/questions/12332843/how-to-disable-render-view-in-zend-framework-2

标签

ajax

zend-framework2