问题
I asked a question earlier today (jquery select2: error in getting data from php-mysql). However, I am trying to fix it and doing that now I am getting bit strange issue. I am not sure why it is happening like this.
Below is the JavaScript code.
<div class="form-group">
<label class="col-sm-4 control-label">Product Name</label>
<div class="col-sm-6">
<input type="hidden" id="tags" style="width: 300px"/>
</div>
</div>
<script type="text/javascript">
var lastResults = [];
$("#tags").select2({
multiple: true,
placeholder: "Please enter tags",
tokenSeparators: [","],
initSelection : function (element, callback) {
var data = [];
$(element.val().split(",")).each(function () {
data.push({id: this, text: this});
});
callback(data);
},
ajax: {
multiple: true,
url: "fetch.php",
dataType: "json",
type: "POST",
data: function(term) {
return {q: term};
},
results: function(data) {
return {results: data};
},
},
createSearchChoice: function (term) {
var text = term + (lastResults.some(function(r) { return r.text == term }) ? "" : " (new)");
return { id: term, text: text };
},
});
$('#tags').on("change", function(e){
if (e.added) {
if (/ \(new\)$/.test(e.added.text)) {
var response = confirm("Do you want to add the new tag "+e.added.id+"?");
if (response == true) {
alert("Will now send new tag to server: " + e.added.id);
/*
$.ajax({
type: "POST",
url: '/someurl&action=addTag',
data: {id: e.added.id, action: add},
error: function () {
alert("error");
}
});
*/
} else {
console.log("Removing the tag");
var selectedTags = $("#tags").select2("val");
var index = selectedTags.indexOf(e.added.id);
selectedTags.splice(index,1);
if (selectedTags.length == 0) {
$("#tags").select2("val","");
} else {
$("#tags").select2("val",selectedTags);
}
}
}
}
});
</script>
Here is the php code (fetch.php)
<?php
// connect to database
require('db.php');
// strip tags may not be the best method for your project to apply extra layer of security but fits needs for this tutorial
$search = strip_tags(trim($_GET['q']));
//$search='te';
// Do Prepared Query
$query = $mysqli->prepare("SELECT tid,tag FROM tag WHERE tag LIKE :search LIMIT 4");
// Add a wildcard search to the search variable
$query->execute(array(':search'=>"%".$search."%"));
// Do a quick fetchall on the results
$list = $query->fetchall(PDO::FETCH_ASSOC);
// Make sure we have a result
if(count($list) > 0){
foreach ($list as $key => $value) {
$data[] = array('id' => $value['tid'], 'text' => $value['tag']);
}
} else {
$data[] = array('id' => '0', 'text' => 'No Products Found');
}
// return the result in json
echo json_encode($data);
?>
select2 version is 3.5
Above code is able to send/receive request from database by using fetch.php.
Problem is in my database there are two records test & temp when I tag any one of them it create new tag.
It should work like this: if database have value then it won't create the new tag with same name.
Update
回答1:
Tags need an id and a text. The issue you're facing is that your text doesn't match the id.
So, even if you write the same text, Select2 thinks the new text is a new option because the id don't match.
To solve your issue, you need to set the id with the same value as the text. Change the foreach of your fetch.php to the following:
foreach ($list as $key => $value) {
$data[] = array('id' => $value['tag'], 'text' => $value['tag']);
}
Update:
You also need to update the variable lastResults to avoid the duplication of tags with the same text. When you bind select2, you need to change the results property of ajax to this (based on this answer:
ajax: {
multiple: true,
url: "fetch.php",
dataType: "json",
type: "POST",
data: function(term) {
return {q: term};
},
results: function(data) {
lastResults = data.results;
return {results: data};
},
},
Note the lastResults = data.results;. Without this, the lastResults variable is always empty and, when the createSearchChoice function is executed, it will always return a new tag.
回答2:
Finally it is working now. I would like to thanks @alex & @milz for their support. Here is the full n final code. Now duplicate tags are not creating. However, i am working to add tag in database.
php/html file
<div class="form-group">
<label class="col-sm-4 control-label">Product Name</label>
<div class="col-sm-6">
<input type="hidden" id="tags" style="width: 300px"/>
</div>
</div>
<script type="text/javascript">
var lastResults = [];
$("#tags").select2({
multiple: true,
tags: true,
placeholder: "Please enter tags",
tokenSeparators: [',', ' '],//[","],
initSelection : function (element, callback) {
var data = [];
$(element.val().split(",")).each(function () {
data.push({id: this, text: this});
});
callback(data);
},
ajax: {
multiple: true,
url: "fetch.php",
dataType: 'json',
// type: "POST",
data: function(term,page) {
return {
term: term
};
},
results: function(data,page) {
lastResults = data;
return {results: data};
},
},
maximumSelectionSize: 3,
minimumInputLength: 3,
createSearchChoice: function(term) {
console.log($(this).attr('data'));
var text = term + (lastResults.some(function(r) {
console.log(r.text);
console.log(term);
return r.text == term
}) ? "" : " (new)");
return {
id: term,
text: text
};
},
});
$('#tags').on("change", function(e){
if (e.added) {
if (/ \(new\)$/.test(e.added.text)) {
var response = confirm("Do you want to add the new tag "+e.added.id+"?");
if (response == true) {
alert("Will now send new tag to server: " + e.added.id);
/*
$.ajax({
type: "POST",
url: '/someurl&action=addTag',
data: {id: e.added.id, action: add},
error: function () {
alert("error");
}
});
*/
} else {
console.log("Removing the tag");
var selectedTags = $("#tags").select2("val");
var index = selectedTags.indexOf(e.added.id);
selectedTags.splice(index,1);
if (selectedTags.length == 0) {
$("#tags").select2("val","");
} else {
$("#tags").select2("val",selectedTags);
}
}
}
}
});
</script>
Here is the php file to get the data from database. fetch.php
<?php
// connect to database
require('db.php');
// strip tags may not be the best method for your project to apply extra layer of security but fits needs for this tutorial
//if(isset($_GET)){
$search = strip_tags(trim($_GET['term']));
// Do Prepared Query
$query = $mysqli->prepare("SELECT tid,tag FROM tag WHERE tag LIKE :search LIMIT 4");
// Add a wildcard search to the search variable
$query->execute(array(':search'=>"%".$search."%"));
$list = $query->fetchall(PDO::FETCH_ASSOC);
if(count($list) > 0){
foreach ($list as $key => $value) {
$data[] = array('id' => $value['tag'], 'text' => $value['tag']);
}
} else {
$data[] = array('id' => 'No Products Found', 'text' => 'No Products Found');
}
echo json_encode($data);
?>
It took lots of time. Almost 3 days. I hope it will save someone efforts.
来源：https://stackoverflow.com/questions/35231584/jquery-select2-duplicate-tag-getting-recreated