问题
I have two vertex classes: Location and User and I have two edges also: Friend and GoingTo. A User can be 'Friend' with another User and a User can also 'GoingTo' a Location. The edge GoingTo has a datetime property called going_date with the date the user is going to the Location.
I want to return every ‘Location’ that has a in(“GoingTo”) edge from an ‘User’ that is a (“Friend”) of a specific starting ‘User’ (#12:11 as example).
What I have here is all locations but without the date property of goingTo...
SELECT expand(both('Friend').out('goingTo')) FROM #12:11
How can I query by this edge property?
回答1:
You can filter on edge's property:
SELECT expand(both('Friend').outE('goingTo')[going_date='2015-01-01'].inV()) FROM #12:11
回答2:
Little late but since this was a high result for my google search, thought I'd link the answer I found on another question.
My use case, and I believe a wide category of use cases leaning on recursion, has to store data in edge properties.
For OP, it should be
SELECT expand(both('Friend').out('goingTo')) FROM #12:11
WHERE out_goingTo[0].going_date = '2015-01-01'
This seems like a case where you'd have 1-many "going to" edges, so it could be
WHERE out_goingTo[0-100] for a range or
WHERE out_goingTo[0,5,10] for a set.
HTH!
来源：https://stackoverflow.com/questions/29157991/orientdb-query-by-edge-property