问题
I was reading through this question, I am not able to grasp the concept used for the 'for loop'
Generally, syntax of for loop is for(assign value, check condition, increment){}
They have used the for loop but there is no condition checking, how does this work?
for(var i = arr1.length; i--;) {
if(arr1[i] !== arr2[i])
return false;
}
回答1:
Actually, it's
for ([initialization]; [condition]; [final-expression])
where all three expressions are optional.
In this case, i-- is a condition, when it reaches 0 it's falsy, and the loop stops.
The "final-expression" is the one not used here.
var arr = [1, 2, 3, 4];
for (var i = arr.length; i--;) {
console.log(arr[i]);
}
The for statement sets the value of i to a positive integer, then on each iteration it evaluates the condition, effectively decrementing i until it reaches a number that is falsy, which happens when i reaches zero.
Here's some other examples of how to skip expressions in a for loop
Skipping the initialization
var i = 0;
for (; i < 4; i++) {
console.log(i);
}
Skipping the condition
for (var i = 0;; i++) {
console.log(i);
if (i > 3) break;
}
Skipping everything
var i = 0;
for (;;) {
if (i > 4) break;
console.log(i);
i++;
}
回答2:
See the code carefully
for(var i = arr1.length; i--;) {
if(arr1[i] !== arr2[i])
return false;
}
Whenever the browser encounters the return statement the control is moved outside the for loop and even outside the function containing this for loop. So, the loops breaks without having a condition when the condition arr1[i] !== arr2[i] is satisfied.
回答3:
All the three arguments in a for loop is optional.
Here the loop iterates with i value changing from arr1.length -> 1. Decrementing i is done in the second argument itself. Since the second argument is for condition checking it will return a falsy value when i becomes zero, and the iteration stops. If the arrays don't match the loop will return false in the middle.
来源:https://stackoverflow.com/questions/46169111/for-loop-without-condition-checking