Why do I have the wrong number of arguments when calling main through reflection?

问题

I have a Class object and I want to invoke a static method. I have the following code.

    Method m=cls.getMethod("main",String[].class);
    System.out.println(m.getParameterTypes().length);
    System.out.println(Arrays.toString(m.getParameterTypes()));
    System.out.println(m.getName());
    m.invoke(null,new String[]{});

This prints:

1
[class [Ljava.lang.String;]
main

But then it then it throws:

IllegalArgumentException: wrong number of arguments

What am I overlooking here?

回答1:

You will have to use

m.invoke(null, (Object)new String[] {});

The invoke(Object, Object...) method accepts a Object.... (Correction) The String[] array passed is used as that Object[] and is empty, so it has no elements to pass to your method invocation. By casting it to Object, you are saying this is the only element in the wrapping Object[].

This is because of array covariance. You can do

public static void method(Object[] a) {}
...
method(new String[] {});

Because a String[] is a Object[].

System.out.println(new String[]{} instanceof Object[]); // returns true

Alternatively, you can wrap your String[] in an Object[]

m.invoke(null, new Object[]{new String[] {}});

The method will then use the elements in the Object[] as arguments for your method invocation.

_{Careful with the StackOverflowError of calling main(..).}

回答2:

And you can do this:

Method m=cls.getMethod("main",String[].class);
System.out.println(m.getParameterTypes().length);
System.out.println(Arrays.toString(m.getParameterTypes()));
System.out.println(m.getName());
String[] a = new String[1];
m.invoke(null,a);

来源：https://stackoverflow.com/questions/22022368/why-do-i-have-the-wrong-number-of-arguments-when-calling-main-through-reflection

标签

java

reflection