问题
I'd like to compile a very basic servlet from command prompt, but it is always unsuccessful and the compiler tells me the following:
error: package javax.servlet does not exist.
I googled for the solution and I found that I need to include the servlet.jar libraries into my PATH.
I believe I did.
I strongly believe that the location for those libraries in my computer is:
C:\apache-tomcat-7.0.23\lib\servlet-api.jar\
and the end (the relevant part) of my PATH is the following:
%JAVA_HOME%\bin;C:\apache-tomcat-7.0.23\lib\servlet-api.jar\
For me, it looks ok, but it is obviously not. Can anyone tell me what could be the problem?
回答1:
classpath not path ... and you don't need it as an evironment variable. You can set the classpath for javac with option -cp or -classpath (several other ways are also available). javac uses the environment variable CLASSPATH to look for classes, that can be useful and can also be a source for hard-to-track-down-problems.
An example to compile a java file that uses a library(that is classes from outside the standard JavaSE) would be:
javac -classpath C:\apache-tomcat-7.0.23\lib\servlet-api.jar MyTestServlet.java
if your environmental variable CLASSPATH contains libraries you need you might want to do:
javac -classpath %CLASSPATH%;C:\apache-tomcat-7.0.23\lib\servlet-api.jar MyTestServlet.java
(please be aware that I don't have access to a windows machine, and therefore haven't tested the idiosyncratic parts of the syntax above) (also note that in this example "C:\apache-tomcat-7.0.23\lib\servlet-api.jar" is a jar file and not a directory which it might be from your question on your machine) For command line compiling on windows OS it is a good idea to have the environmental variable JAVA_HOME set correctly and the bin directory of the JDK in the PATH.
I do however suggest getting to write-compile-execute-deploy via/in an IDE for servlet development before figuring out how to do it with just the JDK from a command line. Java Servlets are not stand-alone executable classes but needs to be deployed into for example tomcat to be tested/used.
回答2:
First copy the servlet-api.jar file from following path
C:\apache-tomcat-7.0.23\lib\servlet-api.jar;
and paste it in the bin folder of java software by following the path
C:\java\jdk1.6\bin;
Hope now you can successfully compile your servlet program.
回答3:
1.You can copy your javax.servlet.jar in the jdk1.6\lib folder. 2.You can go to Control Panel\System\Advanced System Properties\Environment Variables
Enter the location of the jar in the CLASSPATH variable as follows:
Then compile and run the servlet.
来源：https://stackoverflow.com/questions/10363742/how-to-compile-servlets-from-command-prompt