问题
I have a problem with order-only prerequisites. These do not execute first at all. Am I mis-understanding the way order-only prerequisites work?
The following make script:
.PHONY: mefirst mefirst2
mefirst:
@echo "I'm first!"
mefirst2:
@echo "I'm first too!"
normaltarget: normaltarget2 | mefirst2
@echo "normaltarget done"
normaltarget2: a b c
@echo "normaltarget2 done"
helloworld: normaltarget | mefirst
@echo "helloworld done"
.DEFAULT_GOAL := go
go: helloworld
@echo "go done"
a:
@echo a
b:
@echo b
c:
@echo c
...prints out the following:
a
b
c
normaltarget2 done
I'm first too!
normaltarget done
I'm first!
helloworld done
go done
...instead of what I would expect:
I'm first!
I'm first too!
a
b
c
normaltarget2 done
normaltarget done
helloworld done
go done
What am I doing wrong?
回答1:
Am I mis-understanding the way order-only prerequisites work?
Yes, that is what it looks like.
The name "order-only" is somewhat confusing. The prerequisites behind the | are called "order-only prerequisites" not because they change the order of recipe execution inside the list of prerequisites for a single target, but because their only purpose is to have certain targets created before others, like a bootstrap. As accurately explained by user bobbogo below ( -- thanks for correcting): if make decides to rebuild a prerequisite of a target, it will run the recipe for that prerequisite. Now, for an ordinary prerequisite this update implies that the target is now out-of-date, and make will have to run the target's recipe. For an order-only prerequisite on the other hand, make does not mark the target as needing an update.
For example see the section Types of Prerequisites for a use case where a directory should be created before the objects in that directory are created.
Take this example makefile:
a: b
touch a
b: c
touch b
c:
touch c
x: | y
touch x
y: | z
touch y
z:
touch z
As you can see, b and c are normal prerequisites of a and b, whereas y and z are order-only prerequisites of x and y. Starting from a clean slate, they look the same:
:~$ make a
touch c
touch b
touch a
:~$ make x
touch z
touch y
touch x
:~$ make a
make: `a' is up to date.
:~$ make x
make: `x' is up to date.
However, if we now manually "update" the prerequisites at the end of the chain (c and z), we see the difference:
:~$ touch c
:~$ make a
touch b
touch a
:~$ touch z
:~$ make x
make: `x' is up to date.
This shows how order-only prerequisites that exist do not invalidate any targets, independent of their time-stamp. Deleting the order-only target does result in rebuilding though (but only rebuilding of that missing file):
:~$ rm c
:~$ make a
touch c
touch b
touch a
:~$ rm z
:~$ make x
touch z
Having that said, the correct way to change the order in which your recipes are run is by correcting the dependencies between the targets. For example, if you want mefirst to be built before a, then you need to make mefirst a prerequisite for a, as in
a: mefirst
@echo a
It is not possible to give the entire solution to your question since you did not describe in detail in which order you expect recipes to run.
There is a shortcut to your answer which is not the solution but still interesting to know. Although not documented, it seems that the prerequisites of a single target are processed in the order that they appear. The | sign does not change that. In your simple case, you can take advantage of that to achieve the output that you are looking for:
normaltarget: mefirst2 normaltarget2
@echo "normaltarget done"
and
helloworld: mefirst normaltarget
@echo "helloworld done"
However, as pointed out by yourself, this "solution" breaks as soon as the -j flag is used to run recipes in parallel. Also, as pointed out by user bobbogo, relying on this ordering mechanism is bad practice. Introducing new dependencies can interfere with the ordering. So don't do this :-)
来源：https://stackoverflow.com/questions/24821611/order-only-prerequisites-not-working-correctly-in-gnu-make