Symfony2: Inject current user in Service

删除回忆录丶 提交于 2019-12-29 18:34:30

问题


I am trying to inject the currently logged in user into a service. My goal is to extend some twig functionality to output it based on user preferences. In this example I want to output any date function using the user specific Timezone.

There doesn't seem to be any way to inject the current user into a service, which seems really odd to me. When injecting the security context, it doesn't have a token even if the user is logged in

I am using FOS user bundle.

services:
    ...
    twigdate.listener.request:
        class: App\AppBundle\Services\TwigDateRequestListener
        arguments: [@twig, @security.context]
        tags:
            - { name: kernel.event_listener, event: kernel.request, method: onKernelRequest }


<?php

namespace App\AppBundle\Services;

use Symfony\Component\HttpKernel\HttpKernelInterface;
use Symfony\Component\HttpKernel\Event\GetResponseEvent;

class TwigDateRequestListener
{
    protected $twig;

    function __construct(\Twig_Environment $twig, SecurityContext $context) {

        $this->twig = $twig;
        //$this->user = $context->get...;

        var_dump($context); die;
    }

    public function onKernelRequest(GetResponseEvent $event) {
       // $this->twig->getExtension('core')->setDateFormat($user->getProfile()->getFormat());
       // $this->twig->getExtension('core')->setTimeZone($user->getProfile()->getTimezone());
    }
}

output:

object(Symfony\Component\Security\Core\SecurityContext)[325]
  private 'token' => null
  private 'accessDecisionManager' => 
    object(Symfony\Component\Security\Core\Authorization\AccessDecisionManager)[150]
      private 'voters' => 
        array
          0 => 
            object(Symfony\Component\Security\Core\Authorization\Voter\RoleHierarchyVoter)[151]
              ...
          1 => 
            object(Symfony\Component\Security\Core\Authorization\Voter\AuthenticatedVoter)[153]
              ...
          2 => 
            object(Symfony\Component\Security\Acl\Voter\AclVoter)[155]
              ...
      private 'strategy' => string 'decideAffirmative' (length=17)
      private 'allowIfAllAbstainDecisions' => boolean false
      private 'allowIfEqualGrantedDeniedDecisions' => boolean true
  private 'authenticationManager' => 
    object(Symfony\Component\Security\Core\Authentication\AuthenticationProviderManager)[324]
      private 'providers' => 
        array
          0 => 
            object(Symfony\Component\Security\Core\Authentication\Provider\DaoAuthenticationProvider)[323]
              ...
          1 => 
            object(Symfony\Component\Security\Core\Authentication\Provider\AnonymousAuthenticationProvider)[149]
              ...
      private 'eraseCredentials' => boolean true
  private 'alwaysAuthenticate' => boolean false

Am I missing something?


回答1:


I would use a twig extension for that:

class UserDateExtension extends \Twig_Extension
{
    private $context;

    public function __construct(SecurityContext $context)
    {
        $this->context = $context;
    }

    public function getUser()
    {
        return $this->context->getToken()->getUser();
    }

    public function getFilters()
    {
        return array(
            'user_date' => new \Twig_Filter_Method($this, "formatUserDate"),
        );
    }

    public function formatUserDate($date, $format)
    {
        $user = $this->getUser();
        // do stuff
    }

Now in services.xml

    <service id="user_date_twig_extension" class="%user_date_twig_extension.class%">
        <tag name="twig.extension" />
        <argument type="service" id="security.context" />
    </service>

Then in twig you could do:

{{ date | user_date('d/m/Y') }}



回答2:


I think that this question deserves an updated answer since 2.6.x+ since the new security component improvements.

use Symfony\Component\Security\Core\Authentication\Token\Storage\TokenStorage;

class UserDateExtension extends \Twig_Extension
{
    /**
     * @var TokenStorage
     */
    protected $tokenStorage;


    /**
     * @param \Symfony\Component\Security\Core\Authentication\Token\Storage\TokenStorage    $tokenStorage
     */
    public function __construct(TokenStorage $tokenStorage)
    {
        $this->tokenStorage = $tokenStorage;
    }

    public function getUser()
    {
        return $this->tokenStorage->getToken()->getUser();
    }

    public function getFilters()
    {
        return array(
            'user_date' => new \Twig_Filter_Method($this, "formatUserDate"),
        );
    }

    public function formatUserDate($date, $format)
    {
        $user = $this->getUser();
        // do stuff
    }
}

Services.yml

twig.date_extension:
    class: Acme\Twig\SpecialDateExtension
    tags:
        - { name: twig.extension }
    arguments:
        - "@security.token_storage"



回答3:


services.yml

my_service:
    class: ...
    arguments:
        - "@=service('security.token_storage').getToken().getUser()"

Service.php

protected $currentUser;

public function __construct($user)
{
    $this->currentUser = $user;
}

http://symfony.com/doc/current/book/service_container.html#using-the-expression-language




回答4:


The user is a bad candidate to be a service.

  • First it is a model not a service
  • Second there is service security.context where you can get user from.

In a twig template you can use app.user. See symfony doc global-template-variables. If you want to show something based on user permissions you can do {{ is_granted('ROLE_USER') }}.




回答5:


From Symfony 2.6.

You need use @security.token_storage

use Symfony\Component\Security\Core\Authentication\Token\Storage\TokenStorageInterface;

class UserDateExtension extends \Twig_Extension
{
/**
 * @var TokenStorageInterface
 */
protected $tokenStorage;


/**
 * @param $tokenStorage TokenStorage
 */
public function __construct(TokenStorage $tokenStorage)
{
    $this->tokenStorage = $tokenStorage;
}

public function getUser()
{
    return $this->tokenStorage->getToken()->getUser();
}

public function getFilters()
{
    return array(
        'user_date' => new \Twig_Filter_Method($this, "formatUserDate"),
    );
}

public function formatUserDate($date, $format)
{
    $user = $this->getUser();
    // do stuff
}

}

And Services.yml

twig.date_extension:
    class: Acme\Twig\SpecialDateExtension
    tags:
        - { name: twig.extension }
    arguments: ["@security.token_storage"]

reference: http://symfony.com/blog/new-in-symfony-2-6-security-component-improvements




回答6:


I would recommend binding a different event, if you use the kernel.controller event, you will have a token and have no problem. The token is not available in kernel.request since Symfony 2.3

I wrote a guide on how to implement User Timezones for Symfony 2.3+ and 2.6+ in Twig on my blog called Symfony 2.6+ User Timezones.

This is vastly superior to using a Twig Extension because you can use the standard date formatting functions in Twig, as well as provide separate backend UTC date, default Twig date timezones and User defined Twig date timezones.

Here is the most important excerpt:

src/AppBundle/EventListener/TwigSubscriber.php

<?php

namespace AppBundle\EventListener;

use AppBundle\Entity\User;
use Symfony\Component\EventDispatcher\EventSubscriberInterface;
use Symfony\Component\HttpKernel\Event\FilterControllerEvent;
use Symfony\Component\Security\Core\Authentication\Token\Storage\TokenStorageInterface;

class TwigSubscriber implements EventSubscriberInterface
{
    protected $twig;
    protected $tokenStorage;

    function __construct(\Twig_Environment $twig, TokenStorageInterface $tokenStorage)
    {
        $this->twig = $twig;
        $this->tokenStorage = $tokenStorage;
    }

    public static function getSubscribedEvents()
    {
        return [
            'kernel.controller' => 'onKernelController'
        ];
    }

    public function onKernelController(FilterControllerEvent $event)
    {
        $token = $this->tokenStorage->getToken();

        if ($token !== null) {
            $user = $token->getUser();

            if ($user instanceof User) {
                $timezone = $user->getTimezone();
                if ($timezone !== null) {
                    $this->twig->getExtension('core')->setTimezone($timezone);
                }
            }
        }
    }
}

Now you can use twig as normal and it uses your User preferences if available.




回答7:


You can try injecting @service_container and do $this->container->get('security.context')->getToken()->getUser();.



来源:https://stackoverflow.com/questions/9990625/symfony2-inject-current-user-in-service

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!