问题
If I issue the find command as follows:
$ find . -name *.ear
It prints out:
./dir1/dir2/earFile1.ear
./dir1/dir2/earFile2.ear
./dir1/dir3/earFile1.ear
What I want to 'print' to the command line is the name and the size:
./dir1/dir2/earFile1.ear 5000 KB
./dir1/dir2/earFile2.ear 5400 KB
./dir1/dir3/earFile1.ear 5400 KB
回答1:
find . -name '*.ear' -exec ls -lh {} \;
just the h extra from jer.drab.org's reply. saves time converting to MB mentally ;)
回答2:
You need to use -exec or -printf. Printf works like this:
find . -name *.ear -printf "%p %k KB\n"
-exec is more powerful and lets you execute arbitrary commands - so you could use a version of 'ls' or 'wc' to print out the filename along with other information. 'man find' will show you the available arguments to printf, which can do a lot more than just filesize.
[edit] -printf is not in the official POSIX standard, so check if it is supported on your version. However, most modern systems will use GNU find or a similarly extended version, so there is a good chance it will be implemented.
回答3:
a simple solution is to use the -ls option in find:
find . -name \*.ear -ls
That gives you each entry in the normal "ls -l" format. Or, to get the specific output you seem to be looking for, this:
find . -name \*.ear -printf "%p\t%k KB\n"
Which will give you the filename followed by the size in KB.
回答4:
Using gnu find, I think this is what you want. It finds all real files and not directories (-type f), and for each one prints the filename (%p), a tab (\t), the size in kilobytes (%k), the suffix " KB", and then a newline (\n).
find . -type f -printf '%p\t%k KB\n'
If the printf command doesn't format things the way you want, you can use exec, followed by the command you want to execute on each file. Use {} for the filename, and terminate the command with a semicolon (;). On most shells, all three of those characters should be escaped with a backslash.
Here's a simple solution that finds and prints them out using "ls -lh", which will show you the size in human-readable form (k for kilobytes, M for megabytes):
find . -type f -exec ls -lh \{\} \;
As yet another alternative, "wc -c" will print the number of characters (bytes) in the file:
find . -type f -exec wc -c \{\} \;
回答5:
find . -name '*.ear' -exec du -h {} \;
This gives you the filesize only, instead of all the unnecessary stuff.
回答6:
Awk can fix up the output to give just what the questioner asked for. On my Solaris 10 system, find -ls prints size in KB as the second field, so:
% find . -name '*.ear' -ls | awk '{print $2, $11}'
5400 ./dir1/dir2/earFile2.ear
5400 ./dir1/dir2/earFile3.ear
5400 ./dir1/dir2/earFile1.ear
Otherwise, use -exec ls -lh and pick out the size field from the output. Again on Solaris 10:
% find . -name '*.ear' -exec ls -lh {} \; | awk '{print $5, $9}'
5.3M ./dir1/dir2/earFile2.ear
5.3M ./dir1/dir2/earFile3.ear
5.3M ./dir1/dir2/earFile1.ear
回答7:
Why not use du -a ? E.g.
find . -name "*.ear" -exec du -a {} \;
Works on a Mac
回答8:
I struggled with this on Mac OS X where the find command doesn't support -printf.
A solution that I found, that admittedly relies on the 'group' for all files being 'staff' was...
ls -l -R | sed 's/\(.*\)staff *\([0-9]*\)..............\(.*\)/\2 \3/'
This splits the ls long output into three tokens
- the stuff before the text 'staff'
- the file size
- the file name
And then outputs tokens 2 and 3, i.e. output is number of bytes and then filename
8071 sections.php
54681 services.php
37961 style.css
13260 thumb.php
70951 workshops.php
回答9:
This should get you what you're looking for, formatting included (i.e. file name first and size afterward):
find . -type f -iname "*.ear" -exec du -ah {} \; | awk '{print $2"\t", $1}'
sample output (where I used -iname "*.php" to get some result):
./plugins/bat/class.bat.inc.php 20K
./plugins/quotas/class.quotas.inc.php 8.0K
./plugins/dmraid/class.dmraid.inc.php 8.0K
./plugins/updatenotifier/class.updatenotifier.inc.php 4.0K
./index.php 4.0K
./config.php 12K
./includes/mb/class.hwsensors.inc.php 8.0K
回答10:
You could try this:
find. -name *.ear -exec du {} \;
This will give you the size in bytes. But the du command also accepts the parameters -k for KB and -m for MB. It will give you an output like
5000 ./dir1/dir2/earFile1.ear
5400 ./dir1/dir2/earFile2.ear
5400 ./dir1/dir3/earFile1.ear
回答11:
find . -name "*.ear" | xargs ls -sh
回答12:
$ find . -name "test*" -exec du -sh {} \;
4.0K ./test1
0 ./test2
0 ./test3
0 ./test4
$
Scripter World reference
回答13:
Try the following commands:
GNU stat:
find . -type f -name *.ear -exec stat -c "%n %s" {} ';'
BSD stat:
find . -type f -name *.ear -exec stat -f "%N %z" {} ';'
however stat isn't standard, so du or wc could be a better approach:
find . -type f -name *.ear -exec sh -c 'echo "{} $(wc -c < {})"' ';'
回答14:
find . -name "*.ear" -exec ls -l {} \;
来源：https://stackoverflow.com/questions/64649/how-do-i-get-the-find-command-to-print-out-the-file-size-with-the-file-name