How do I convert a JSONObject to class object?

问题

I need to convert a JSONObject to a Location object using gson libraries for an android project of mine. I'm not sure on how to do this. Can anyone help me with this. Thanks in advance.

I have a code something like

JSONArray input = new JSONArray(extras.getString("loc_json"));

I wanted to convert the JSONObject taken from the JSONArray to a Location class object. I just wanted to know whether there is a function that does it directly.

Pardon me if I framed the question in a wrong way. Since I haven't got the direct function, I did it in this way.

 loc_temp = (Location) gson.fromJson(input.getJSONObject(i).toString(), Location.class);;

Sorry for the stupid question.

回答1:

Here's a tutorial for GSON - I think it should help bolster your understanding. Essentially the parsing is done like this:

String mJsonString = "...";
JsonParser parser = new JsonParser(); 
JsonElement mJson =  parser.parse(mJsonString);
Gson gson = new Gson();
MyDataObject object = gson.fromJson(mJson, MyDataObject.class);

回答2:

if you still want to use org.json.JSONObject:

org.json.JSONObject o;
ObjectMapper m = new ObjectMapper();
MyClass myClass = m.readValue(o.toString(), MyClass.class);

回答3:

use com.google.gson.JsonObject & JsonArray instead of org.json.*

like this :

Gson gson = new Gson();
Type typeOfT = new TypeToken<List<Location.class>>(){}.getType();
JsonParser parser = new JsonParser();
JsonObject jo = (JsonObject) parser.parse(jsonStr);
JsonArray ja = jo.getAsJsonArray("memberName");
list = gson.fromJson(ja, typeOfT);

来源：https://stackoverflow.com/questions/15282181/how-do-i-convert-a-jsonobject-to-class-object

标签

android

gson