JAX-WS client without a WSDL document file

与世无争的帅哥 提交于 2019-12-28 05:46:26

问题


I am consuming a webservice soa, with netbeans (jax-ws) i use netbeans auto generate client, and all run fine, but i see that the wsdl is always downloading while the client is running.

In production i don't want expose the wsdl, and i am trying to modify the client for don't require wsdl, all my intends are wrong, i find this:

WebService_Service svc = new WebService_Service(
  null,
  new QName("http://www.example.com/ws", "WebService"));
WebService port = svc.getPort(WebService.class);
BindingProvider bindingProvider = (BindingProvider) port;
bindingProvider.getRequestContext()
  .put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY,
    "http://www.example.com/real_endpoint_url_goes_here");

but when the first line is executed i found this exception:

Message: El contenido no está permitido en el prólogo.
    at com.sun.xml.internal.ws.streaming.XMLStreamReaderUtil.wrapException(Unknown Source)
    at com.sun.xml.internal.ws.streaming.XMLStreamReaderUtil.next(Unknown Source)
    at com.sun.xml.internal.ws.streaming.XMLStreamReaderUtil.nextContent(Unknown Source)
    at com.sun.xml.internal.ws.streaming.XMLStreamReaderUtil.nextElementContent(Unknown Source)
    at com.sun.xml.internal.ws.wsdl.parser.RuntimeWSDLParser.hasWSDLDefinitions(Unknown Source)
    at com.sun.xml.internal.ws.wsdl.parser.RuntimeWSDLParser.parse(Unknown Source)
    at com.sun.xml.internal.ws.wsdl.parser.RuntimeWSDLParser.parse(Unknown Source)
    at com.sun.xml.internal.ws.client.WSServiceDelegate.parseWSDL(Unknown Source)
    at com.sun.xml.internal.ws.client.WSServiceDelegate.<init>(Unknown Source)
    at com.sun.xml.internal.ws.client.WSServiceDelegate.<init>(Unknown Source)
    at com.sun.xml.internal.ws.spi.ProviderImpl.createServiceDelegate(Unknown Source)
    at javax.xml.ws.Service.<init>(Unknown Source)

Any idea to ignore wsdl?


回答1:


There are several ways, of which I will tell you two:

  1. Use a WSDL document file locally

    Save a copy of the WSDL document file and the schemma files to your project.

    ClassLoader classloader = Thread.currentThread().getContextClassLoader();
    URL wsdlLocation = classloader.getResource("MyHelloService.wsdl");
    QName serviceName= new QName("http://test.com/", "MyHelloService");
    
    MyHelloService service = new MyHelloService(wsdlLocation, serviceName);
    service.sayHello("Test");
    

    You may combine the WSDL document file with the schema files.

  2. Without a WSDL document file

    This solution requires the client generated.

    QName qname = new QName("http://thenamespace", "FooService");
    FooService service = new FooService(null, qname); // null for ignore WSDL
    Foo port = service.getFooPort();
    BindingProvider bindingProvider = (BindingProvider) port;
    bindingProvider.getRequestContext()
        .put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY,
        "http://foo.com/soap/fooBean");
    
    // Use the service
    String result = port.doSomething(param);
    



回答2:


Finally i use the CXF libraries and i achieve use the Paul Vargas answer:

Without a WSDL document file

This solution requires the client generated.

QName qname = new QName("http://thenamespace", "FooService");
FooService service = new FooService(null, qname); // null for ignore WSDL
Foo port = service.getFooPort();
BindingProvider bindingProvider = (BindingProvider) port;
bindingProvider.getRequestContext()
    .put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY,
    "http://foo.com/soap/fooBean");

// Use the service
String result = port.doSomething(param);

Using standard jaw-ws, this solution don't work, CXF is necessary.




回答3:


I needed something like this, too.

In my case, I had put a dummy wsdl without endpoint address inside my web app classpath. After that, I set a valid address at runtime, like this:

    String WSDL = "/config/ws/Main_default.wsdl";
    Main service = new Main(Main.class.getResource(WSDL), new QName(
            "http://www.example.com/", "Main"));
    MainWS port = service.getMainWSPort();

    BindingProvider bindingProvider = (BindingProvider) port;
    bindingProvider.getRequestContext().put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY,
            "http://app.example.com/ws/services/main");

    Object result = port.someMethod("some param");



回答4:


This exception happens while there is a parse error in your xml and there is something wrong at the specified row and column. Check your xml



来源:https://stackoverflow.com/questions/19815145/jax-ws-client-without-a-wsdl-document-file

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