how to return two dimensional char array c++?

问题

i ve created two dimensional array inside a function, i want to return that array, and pass it somewhere to other function..

char *createBoard( ){  
  char board[16][10];
  int j =0;int i = 0;
  for(i=0; i<16;i++){
        for( j=0;j<10;j++){   
                board[i][j]=(char)201;
        }   
  }
  return board;
}

but this keeps giving me error

回答1:

Yeah see what you are doing there is returning a pointer to a object (the array called board) which was created on the stack. The array is destroyed when it goes out of scope so the pointer is no longer pointing to any valid object (a dangling pointer).

You need to make sure that the array is allocated on the heap instead, using new. The sanctified method to create a dynamically allocated array in modern C++ is to use something like the std::vector class, although that's more complicated here since you are trying to create a 2D array.

char **createBoard()
{
    char **board=new char*[16];
    for (int i=0; i<16; i++)
    {
       board[i] = new char[10];
       for (int j=0; j<10; j++)
         board[i][j]=(char)201;
    }

    return board;
}

void freeBoard(char **board)
{
    for (int i=0; i<16; i++)
      delete [] board[i];
    delete [] board;
}

回答2:

The best approach is create a board class and make the ctreateBoard function its constructor:

class Board {
  private:
   char mSquares[16][10];

   public:
    Board() {
        for(int i=0; i<16;i++){
        for( int j=0;j<10;j++){   
                mSquares[i][j]=201;
        }       
    }

   // suitable member functions here
 };

For information on how to use such a class, there is no substitute for reading a good book. I strongly recommend Accelerated C++ by Andrew Koenig and Barbra Moo.

回答3:

This approach will not work. If you return a pointer to a local variable you'll run into undefined behaviour. Instead allocate an array on heap with new and copy data into it manually indexing it.

回答4:

I would really recommend using STL vector<> or boost/multi_array containers for this.

If you must use arrays, then I would recommend using a typedef to define the array.

typedef char[16][10] TBoard;

You could also return

 char**

...but then you would need to typecast it to the correct size in order to index it correctly. C++ does not support dynamic multiple dimension arrays.

Also as others have suggested you can't return an object on the stack (i.e., local variable)

回答5:

Don't return pointer to a local variable, as other mentioned. If I were forced to do what you want to achieve, first I'd go for std::vector. Since you haven't learnt std::vector, here is another way:

void createBoard(char board[16][10])
{  
  int j =0;int i = 0;
  for(i=0; i<16;i++){
        for( j=0;j<10;j++){   
                board[i][j]=(char)201;
        }       
  }
}

回答6:

You should return char** instead of char*

回答7:

The simple answer to your question is char**.

Having said that, DON'T DO IT ! Your "board" variable won't last outside createBoard().

Use boost::multi_array and pass it as a reference to createBoard() or return it directly (but if you do that, it will be copied).

回答8:

You must not return a pointer to a functions local variables because this space gets overwritten as soon as the function returns.

The storage associated with board is on the function's stack.

来源：https://stackoverflow.com/questions/720707/how-to-return-two-dimensional-char-array-c

标签

c++

arrays

multidimensional-array