Python: BeautifulSoup - get an attribute value based on the name attribute

问题

I want to print an attribute value based on its name, take for example

<META NAME="City" content="Austin">

I want to do something like this

soup = BeautifulSoup(f) //f is some HTML containing the above meta tag
for meta_tag in soup('meta'):
    if meta_tag['name'] == 'City':
         print meta_tag['content']

The above code give a KeyError: 'name', I believe this is because name is used by BeatifulSoup so it can't be used as a keyword argument.

回答1:

It's pretty simple, use the following -

>>> from bs4 import BeautifulSoup
>>> soup = BeautifulSoup('<META NAME="City" content="Austin">')
>>> soup.find("meta", {"name":"City"})
<meta name="City" content="Austin" />
>>> soup.find("meta", {"name":"City"})['content']
u'Austin'

Leave a comment if anything is not clear.

回答2:

theharshest answered the question but here is another way to do the same thing. Also, In your example you have NAME in caps and in your code you have name in lowercase.

s = '<div class="question" id="get attrs" name="python" x="something">Hello World</div>'
soup = BeautifulSoup(s)

attributes_dictionary = soup.find('div').attrs
print attributes_dictionary
# prints: {'id': 'get attrs', 'x': 'something', 'class': ['question'], 'name': 'python'}

print attributes_dictionary['class'][0]
# prints: question

print soup.find('div').get_text()
# prints: Hello World

回答3:

The following works:

from bs4 import BeautifulSoup

soup = BeautifulSoup('<META NAME="City" content="Austin">', 'html.parser')

metas = soup.find_all("meta")

for meta in metas:
    print meta.attrs['content'], meta.attrs['name']

回答4:

theharshest's answer is the best solution, but FYI the problem you were encountering has to do with the fact that a Tag object in Beautiful Soup acts like a Python dictionary. If you access tag['name'] on a tag that doesn't have a 'name' attribute, you'll get a KeyError.

回答5:

6 years late to the party but I've been searching for how to extract an html element's tag attribute value, so for:

<span property="addressLocality">Ayr</span>

I want "addressLocality". I kept being directed back here, but the answers didn't really solve my problem.

How I managed to do it eventually:

>>> from bs4 import BeautifulSoup as bs

>>> soup = bs('<span property="addressLocality">Ayr</span>', 'html.parser')
>>> my_attributes = soup.find().attrs
>>> my_attributes
{u'property': u'addressLocality'}

As it's a dict, you can then also use keys and 'values'

>>> my_attributes.keys()
[u'property']
>>> my_attributes.values()
[u'addressLocality']

Hopefully it helps someone else!

回答6:

One can also try this solution :

To find the value, which is written in span of table

htmlContent

<table>
    <tr>
        <th>
            ID
        </th>
        <th>
            Name
        </th>
    </tr>


    <tr>
        <td>
            <span name="spanId" class="spanclass">ID123</span>
        </td>

        <td>
            <span>Bonny</span>
        </td>
    </tr>
</table>

Python code

soup = BeautifulSoup(htmlContent, "lxml")
soup.prettify()

tables = soup.find_all("table")

for table in tables:
   storeValueRows = table.find_all("tr")
   thValue = storeValueRows[0].find_all("th")[0].string

   if (thValue == "ID"): # with this condition I am verifying that this html is correct, that I wanted.
      value = storeValueRows[1].find_all("span")[0].string
      value = value.strip()

      # storeValueRows[1] will represent <tr> tag of table located at first index and find_all("span")[0] will give me <span> tag and '.string' will give me value

      # value.strip() - will remove space from start and end of the string.

     # find using attribute :

     value = storeValueRows[1].find("span", {"name":"spanId"})['class']
     print value
     # this will print spanclass

来源：https://stackoverflow.com/questions/11205386/python-beautifulsoup-get-an-attribute-value-based-on-the-name-attribute

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python

beautifulsoup