问题
I ran a sample program and indeed destructors for stack-allocated objects are called, but is this guaranteed by the standard?
回答1:
Yes, it is guaranteed (provided the exception is caught), down to the order in which the destructors are invoked:
C++11 15.2 Constructors and destructors [except.ctor]
1 As control passes from a throw-expression to a handler, destructors are invoked for all automatic objects constructed since the try block was entered. The automatic objects are destroyed in the reverse order of the completion of their construction.
Furthermore, if the exception is thrown during object construction, the subobjects of the partially-constructed object are guaranteed to be correctly destroyed:
2 An object of any storage duration whose initialization or destruction is terminated by an exception will have destructors executed for all of its fully constructed subobjects (excluding the variant members of a union-like class), that is, for subobjects for which the principal constructor (12.6.2) has completed execution and the destructor has not yet begun execution. Similarly, if the non-delegating constructor for an object has completed execution and a delegating constructor for that object exits with an exception, the object’s destructor will be invoked. If the object was allocated in a new-expression, the matching deallocation function (3.7.4.2, 5.3.4, 12.5), if any, is called to free the storage occupied by the object.
This whole process is known as "stack unwinding":
3 The process of calling destructors for automatic objects constructed on the path from a try block to a throw-expression is called “stack unwinding.” If a destructor called during stack unwinding exits with an exception, std::terminate is called (15.5.1).
Stack unwinding forms the basis of the widely-used technique called Resource Acquisition Is Initialization (RAII).
Note that stack unwinding is not necessarily done if the exception is not caught. In this case it's up to the implementation whether stack unwinding is done. But whether stack unwinding is done or not, in this case you're guaranteed a final call to std::terminate.
C++11 15.5.1 The std::terminate() function [except.terminate]
2 … In the situation where no matching handler is found, it is implementation-defined whether or not the stack is unwound before
std::terminate()is called.
回答2:
Yes, destructors are guaranteed to be called on stack unwinding, including unwinding due to exception being thrown. There are only few tricks with exceptions that you have to remember:
- Destructor of the class is not called if exception is thrown in its constructor.
- Exception is automatically re-thrown if caught in construction initialization list catch block.
回答3:
If a throw is caught then normally cpp operations continue. This include destructors and stack popping. However if the exception is not caught, stack popping is not guaranteed.
Also a bare throw or empty throw cannot be caught by my mobile compiler.
example:
#include <Jav/report.h>
int main()
{
try { throw; }
catch(...) { rep("I bet this is not caught"); }
}
来源：https://stackoverflow.com/questions/8311457/are-destructors-called-after-a-throw-in-c