Json.Net: Serialize/Deserialize property as a value, not as an object

问题

How can I achieve the following JSON representation of Id class when used in another class?

class Car
{
    public StringId Id { get; set; }
    public string Name { get; set; }
}

class StringId
{
    public string Value { get; set; }
}

// ---------------------------------------------

// Desired representation
{ "Id": "someId", "Name": "Ford" }

// Default (undesired) representation
{ "Id" : { "Value": "someId" }, "Name": "Ford" }

回答1:

You could add a TypeConverter for StringId. Json.NET will pick up the type converter and use it to convert it from and to a string:

[TypeConverter(typeof(StringIdConverter))]
class StringId
{
    public string Value { get; set; }
}

class StringIdConverter : TypeConverter
{
    public override bool CanConvertFrom(ITypeDescriptorContext context, Type sourceType)
    {
        if (sourceType == typeof(string))
            return true;
        return base.CanConvertFrom(context, sourceType);
    }

    public override bool CanConvertTo(ITypeDescriptorContext context, Type destinationType)
    {
        if (destinationType == typeof(StringId))
            return true;
        return base.CanConvertTo(context, destinationType);
    }

    public override object ConvertFrom(ITypeDescriptorContext context, System.Globalization.CultureInfo culture, object value)
    {
        if (value is string)
        {
            return new StringId { Value = (string)value };
        }
        return base.ConvertFrom(context, culture, value);
    }

    public override object ConvertTo(ITypeDescriptorContext context, System.Globalization.CultureInfo culture, object value, Type destinationType)
    {
        if (destinationType == typeof(string) && value is StringId)
        {
            return ((StringId)value).Value;
        }
        return base.ConvertTo(context, culture, value, destinationType);
    }
}

If your string representation contains embedded numeric or date/time data, be sure to convert that data using the culture passed in rather than the default, current culture. Json.NET will call the converter with the correct culture, which is the invariant culture by default, thus ensuring the generated JSON files are portable between cultures.

Sample fiddle.

Note however that, if you are using .Net Core, support for type converters was only added as of Json.NET 10.0.1. And support for type converters in Json.NET Portable builds is not available as of 10.0.3.

Alternatively, if you don't mind adding Json.NET-specific attributes to your type, you could use a custom JsonConverter:

[JsonConverter(typeof(StringIdConverter))]
class StringId
{
    public string Value { get; set; }
}

class StringIdConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(StringId);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        if (reader.TokenType == JsonToken.Null)
            return null;
        var token = JToken.Load(reader);
        return new StringId { Value = (string)token };
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        var id = (StringId)value;
        writer.WriteValue(id.Value);
    }
}

You can also set the converter in global settings.

Sample fiddle.

回答2:

You can override the ToString method of the StringId class to return the value

    public override string ToString()
    {
        return this.Value;
    }

You will need a TypeConverter later to deserialize from string to StringId

public class StringIdConverter : TypeConverter
{
    public override bool CanConvertFrom(ITypeDescriptorContext context, Type sourceType)
    {
        if (sourceType == typeof(string))
        {
            return true;
        }
        return base.CanConvertFrom(context, sourceType);
    }


    public override object ConvertFrom(ITypeDescriptorContext context, CultureInfo culture, object value)
    {
        if (value is string)
        {
            return new StringId(value.ToString());
        }
        return base.ConvertFrom(context, culture, value);
    }
}

And decorate your StringId class with this attribute

[TypeConverter(typeof(StringIdConverter))]
public class StringId{
    ...
}

来源：https://stackoverflow.com/questions/40480489/json-net-serialize-deserialize-property-as-a-value-not-as-an-object