Newtonsoft JSON Deserialize

问题

My JSON is as follows:

{"t":"1339886","a":true,"data":[],"Type":[['Ants','Biz','Tro']]}

I found the Newtonsoft JSON.NET deserialize library for C#. I tried to use it as follow:

object JsonDe = JsonConvert.DeserializeObject(Json);

How can I access to the JsonDe object to get all the "Type" Data? I tried it with a loop but it is not working because the object does not have an enumerator.

回答1:

You can implement a class that holds the fields you have in your JSON

class MyData
{
    public string t;
    public bool a;
    public object[] data;
    public string[][] type;
}

and then use the generic version of DeserializeObject:

MyData tmp = JsonConvert.DeserializeObject<MyData>(json);
foreach (string typeStr in tmp.type[0])
{
    // Do something with typeStr
}

Documentation: Serializing and Deserializing JSON

回答2:

A much easier solution: Using a dynamic type

As of Json.NET 4.0 Release 1, there is native dynamic support. You don't need to declare a class, just use dynamic :

dynamic jsonDe = JsonConvert.DeserializeObject(json);

All the fields will be available:

foreach (string typeStr in jsonDe.Type[0])
{
    // Do something with typeStr
} 

string t = jsonDe.t;
bool a = jsonDe.a;
object[] data = jsonDe.data;
string[][] type = jsonDe.Type;

With dynamic you don't need to create a specific class to hold your data.

回答3:

As per the Newtonsoft Documentation you can also deserialize to an anonymous object like this:

var definition = new { Name = "" };

string json1 = @"{'Name':'James'}";
var customer1 = JsonConvert.DeserializeAnonymousType(json1, definition);

Console.WriteLine(customer1.Name);
// James

来源：https://stackoverflow.com/questions/17038810/newtonsoft-json-deserialize

标签

json.net

deserialization