by combining base url getting text out of image in python using scrapy?

问题

i tried this code :

src1 = "https://hms.harvard.edu/"<br/>
src = response.css('div.person-line > div > 
      img::attr("src")').extract_first()<br/>
src = sites/default/files/hms-faculty-emails/BX0UVXkP.jpg <br/>
import urlparse <br/>
urlparse.urljoin(src1, src)<br/>
https://hms.harvard.edu/sites/default/files/hms-faculty-emails/BX0UVXkP.jpg<br/>
src2 = urlparse.urljoin(src1,src)<br/>
email = pytesseract.image_to_string(Image.open(src2))<br/>

i'm getting this error

ioerror errno 22 invalid mode ('rb') or filename

how to get email text out of text image..can any one help please?

回答1:

You should use io.BufferIO buffer, because you call function image_to_string with http path. You need write code like this:

def get_text(src):
    response = urlopen(src)
    buffer = io.BytesIO(response.read())
    return pytesseract.image_to_string(Image.open(buffer))

来源：https://stackoverflow.com/questions/46169963/by-combining-base-url-getting-text-out-of-image-in-python-using-scrapy