问题
I'm trying to allocate an array of pointers to a struct but there's something wrong with my code.
This is my struct:
struct Brick {
GameObject2D* handle_;
};
Brick** bricks_;
And this is how i'm trying to allocate memory for it:
int bricks_amount_ = 10;
bricks_ = (Brick**)malloc(sizeof(Brick*) * bricks_amount_);
The program crash. I've make a devenv on it to debug where's the problem and it crash on this line:
for (unsigned short int i = 0; i < bricks_amount_; i++){
bricks_[i]->handle_ = new GameObject2D(); <---------- CRASH!
}
Any suggestions?
PS: Sorry for my english :P
=========================================================================
[SOLUTION]
Finally i've decided to use std::vector instead raw pointers:
bricks_.resize(bricks_amount_);
but i've tried to make the malloc different way and it works too:
bricks_ = (struct Brick*)malloc(sizeof(struct Brick) * bricks_amount_);
or this:
bricks_ = new Brick[bricks_amount_];
Thank you to the people who wants to help!
回答1:
It's C++:
- don't use
malloc, usenew - don't use plain arrays, use
std::vectororstd::array - don't use raw pointers, use
std::unique_ptr
回答2:
Do not use
Bricks ** //will be a 2 dimensional array
Use instead
Bricks * //will be a 1 dimensioanal array
If you want a single dimensional array
Then do
`Bricks * bricks_ = (Bricks *)malloc(sizeof(Brick) * bricks_amount_ );
`
Then you can safely do without a crash
for (unsigned short int i = 0; i < bricks_amount_; i++){
bricks_[i]->handle_ = new GameObject2D(); <---------- There will not be CRASH!
}
来源:https://stackoverflow.com/questions/37378199/failed-to-allocate-an-array-of-pointers-to-a-struct