How do I extract the email address using scrapy?

问题

I'm trying to extract the email address of each restaurant on TripAdvisor.

I've tried this but keeps returning an [ ]:

response.xpath('//*[@class= "restaurants-detail-overview-cards-LocationOverviewCard__detailLink--iyzJI restaurants-detail-overview-cards-LocationOverviewCard__contactItem--89flT6"]')

Code snippet off the TripAdvisor page is below:

<div class="restaurants-detail-overview-cards-LocationOverviewCard__detailLink--iyzJI restaurants-detail-overview-cards-LocationOverviewCard__contactItem--1flT6"><span><a href="mailto:info@canopylounge.my?subject=?"><span class="ui_icon email restaurants-detail-overview-cards-LocationOverviewCard__detailLinkIcon--T_k32"></span><span class="restaurants-detail-overview-cards-LocationOverviewCard__detailLinkText--co3ei">Email</span><span class="ui_icon external-link-no-box restaurants-detail-overview-cards-LocationOverviewCard__upLinkIcon--1oVn1"></span></a></span></div>

回答1:

First: you had mistake in class name.

Second: it is class in <div> but @href is in <a>. And <a> is not directly after <div> so you need

'//*[@class="..."]//a/@href'

(I skip class name because it is too long to display it)

But instead of so long class name you can try

'//a[contains(@href, "mailto")]/@href'

I tested xpath using lxml

text = '''<div class="restaurants-detail-overview-cards-LocationOverviewCard__detailLink--iyzJI restaurants-detail-overview-cards-LocationOverviewCard__contactItem--1flT6">
<span><a href="mailto:info@canopylounge.my?subject=?">
<span class="ui_icon email restaurants-detail-overview-cards-LocationOverviewCard__detailLinkIcon--T_k32"></span>
<span class="restaurants-detail-overview-cards-LocationOverviewCard__detailLinkText--co3ei">Email</span>
<span class="ui_icon external-link-no-box restaurants-detail-overview-cards-LocationOverviewCard__upLinkIcon--1oVn1"></span>
</a></span>
</div>'''

import lxml.html

soup = lxml.html.fromstring(text)

print(soup.xpath('//*[@class="restaurants-detail-overview-cards-LocationOverviewCard__detailLink--iyzJI restaurants-detail-overview-cards-LocationOverviewCard__contactItem--1flT6"]//a/@href'))
print(soup.xpath('//a[contains(@href, "mailto")]/@href'))

回答2:

This is one of the ways how you can:

import requests
from scrapy import Selector

site_link = 'https://www.tripadvisor.com/Restaurant_Review-g60713-d11882449-Reviews-Coin_Op_Game_Room-San_Francisco_California.html'

res = requests.get(site_link)
sel = Selector(res)
email = sel.xpath("//*[contains(@class,'LocationOverviewCard__contactItem--')]//a[contains(@href,'mailto:')]/@href").get()
email = email.split("mailto:")[1].split("?")[0] if email else ""
print(email)

Output:

info@coinopsf.com

回答3:

Selector also has a .re() method for extracting data using regular expressions.

In [2]: response.xpath('//a[contains(@href, "mailto")]/@href')
Out[2]: [<Selector xpath='//a[contains(@href, "mailto")]/@href' data='mailto:info@coinopsf.com?subject=?'>]

In [3]: response.xpath('//a[contains(@href, "mailto")]/@href').get()
Out[3]: 'mailto:info@coinopsf.com?subject=?'

In [4]: response.xpath('//a[contains(@href, "mailto")]/@href').re('mailto:(.*)\?\w')
Out[4]: ['info@coinopsf.com']
In [5]: response.xpath('//a[contains(@href, "mailto")]/@href').re('mailto:([^?]*)')
Out[5]: ['info@coinopsf.com']

来源：https://stackoverflow.com/questions/58426462/how-do-i-extract-the-email-address-using-scrapy

标签

python

web-scraping

scrapy