问题
I'm learning assembly programming and I've been tasked with converting a for loop (along with any array use) into assembly within my program.
The program simply takes an encryption key (EKey) and uses it to encrypt an array of letters (hello for example).
Here is the loop in C++:
void encrypt_chars(int length, char EKey)
{
char temp_char; // char temporary store
for (int i = 0; i < length; i++) // encrypt characters one at a time
{
temp_char = OChars[i]; // temp_char now contains the address values of the individual character
__asm
{
push eax // Save values contained within register to stack
push ecx
movzx ecx, temp_char
push ecx // Push argument #2
lea eax, EKey
push eax // Push argument #1
call encrypt
add esp, 8 // Clean parameters of stack
mov temp_char, al // Move the temp character into a register
pop ecx
pop eax
}
EChars[i] = temp_char; // Store encrypted char in the encrypted chars array
}
return;
// Inputs: register EAX = 32-bit address of Ekey,
// ECX = the character to be encrypted (in the low 8-bit field, CL).
// Output: register EAX = the encrypted value of the source character (in the low 8-bit field, AL).
__asm
{
encrypt:
push ebp // Set stack
mov ebp, esp // Set up the base pointer
mov eax, [ebp + 8] // Move value of parameter 1 into EAX
mov ecx, [ebp + 12] // Move value of parameter 2 into ECX
push edi // Used for string and memory array copying
push ecx // Loop counter for pushing character onto stack
not byte ptr[eax] // Negation
add byte ptr[eax], 0x04 // Adds hex 4 to EKey
movzx edi, byte ptr[eax] // Moves value of EKey into EDI using zeroes
pop eax // Pop the character value from stack
xor eax, edi // XOR character to give encrypted value of source
pop edi // Pop original address of EDI from the stack
rol al, 1 // Rotates the encrypted value of source by 1 bit (left)
rol al, 1 // Rotates the encrypted value of source by 1 bit (left) again
add al, 0x04 // Adds hex 4 to encrypted value of source
mov esp, ebp // Deallocate values
pop ebp // Restore the base pointer
ret
}
//--- End of Assembly code
}
I've looked at the disassembly code and used that to rewrite the ASM code. I typed in the disassembly code as follows however it gives the following errors: http://gyazo.com/3b6875c9e1207df61df4e95506af7ed6
Here is my code:
void encrypt_chars(int length, char EKey)
{
char temp_char;
__asm
{
mov DWORD PTR[rbp - 4], 0
jmp L2
L3:
mov eax, DWORD PTR[rbp - 4]
cdqe
cltq
// ERROR HERE ^ above: error C2400: inline assembler syntax error in 'opcode'; found 'newline'
movzx eax, BYTE PTR EChars[rax]
// ERROR HERE ^ above: error C2400: inline assembler syntax error in 'opcode'; found 'newline'
// another error ^ above: error C2424: '[' : improper expression in 'second operand'
mov BYTE PTR[rbp - 5], al
// OG code
push eax // Save values contained within register to stack
push ecx
movzx ecx, temp_char
push ecx // Push argument #2
lea eax, EKey
push eax // Push argument #1
call encrypt4
add esp, 8 // Clean parameters of stack
mov temp_char, al // Move the temp character into a register
pop ecx
pop eax
// end of OG code
mov eax, DWORD PTR[rbp - 4]
cdqe
movzx edx, BYTE PTR[rbp - 5] // ERROR HERE: error C2400: inline assembler syntax error in 'opcode'; found 'newline'
mov BYTE PTR DChars[rax], dl // ERROR HERE: error C2424: '[' : improper expression in 'first operand'
L2:
mov eax, DWORD PTR[rbp - 4]
cmp eax, DWORD PTR[rbp - 20]
jl L3
}
return;
__asm
{
encrypt4:
push ebp // Set stack
mov ebp, esp // Set up the base pointer
mov eax, [ebp + 8] // Move value of parameter 1 into EAX
mov ecx, [ebp + 12] // Move value of parameter 2 into ECX
push edi // Used for string and memory array copying
push ecx // Loop counter for pushing character onto stack
not byte ptr[eax] // Negation
add byte ptr[eax], 0x04 // Adds hex 4 to EKey
movzx edi, byte ptr[eax] // Moves value of EKey into EDI using zeroes
pop eax // Pop the character value from stack
xor eax, edi // XOR character to give encrypted value of source
pop edi // Pop original address of EDI from the stack
rol al, 1 // Rotates the encrypted value of source by 1 bit (left)
rol al, 1 // Rotates the encrypted value of source by 1 bit (left) again
add al, 0x04 // Adds hex 4 to encrypted value of source
mov esp, ebp // Deallocate values
pop ebp // Restore the base pointer
ret
}
//--- End of Assembly code
}
Would anyone be able to point out where I'm going wrong please? I'm finding this relatively difficult so step-by-step explanations are most welcome. Please let me know where I'm going wrong. Thanks x
EDIT:
My full code: http://pastebin.com/tP9Dgvpn
回答1:
Try this:
void encrypt_chars(int length, char EKey, char *Msg)
{
int InLength = length;
int counter;
__asm
{
push eax // Counter
mov eax, 0 // Zero counter
push ebx // Value
mov ebx, InLength
jmp L2
L3:
mov counter, EAX
call encrypt4
inc eax // Increment counter.
L2:
cmp eax, ebx
jl L3 // Jump if we haven't reached our count.
pop ebx
pop eax
}
return;
__asm
{
encrypt4:
push eax
push ebx
push edi
mov ebx, counter
add ebx, Msg
mov al, [ebx] // Move character into al
CBW // Make word.
CWDE // Make Dword.
not byte ptr[EKey] // Negation
add byte ptr[EKey], 0x04 // Adds hex 4 to EKey
movzx edi, byte ptr[EKey] // Moves value of EKey into EDI using zeroes
xor eax, edi // XOR character to give encrypted value of source
pop edi // Pop original address of EDI from the stack
rol al, 1 // Rotates the encrypted value of source by 1 bit (left)
rol al, 1 // Rotates the encrypted value of source by 1 bit (left) again
add al, 0x04 // Adds hex 4 to encrypted value of source
mov [ebx], al
pop ebx
pop eax
ret
}
//--- End of Assembly code
}
I call it with this snippet:
EKey = 'i';
sprintf(OChars, "hello");
printf("%s\n", OChars);
encrypt_chars(sizeof(OChars), EKey, OChars);
printf("%s\n", OChars);
My output looks like this: hello
╧4▀↑█⌐
This matches your output but all except the first character. I am convinced the algorithm looks correct and I can't spend any more time on it. I believe it can be differences in character sets. Try it out.
Good luck!
来源：https://stackoverflow.com/questions/29921422/high-level-to-asm-conversion