Regex that wil match after keyword and before question mark

问题

I'm getting stuck on regex101 with the following test string:

https://localhost:8443/site/recipes/recepten-zoeken/menugang:hoofdgerecht/soort:italiaans/seizoen:winter?Nrpp=24

I'm trying to match everything in between: recepten-zoeken/ and ?

My current tries lead me nowhere as i'm very novice writing regexes. Anyone wanting to chip in?

This is what I currently have:

.(?=([^/recepten-zoeken/]?)*$)

回答1:

Use capturing group.(() brackets indicates capturing group)

Capture upto last question mark

Try this regex \/recepten-zoeken\/(.*)\?

Explanation:-

\/ Match forward slash
recepten-zoeken Match literally
\/ Match forward slash
(.*) Capture in a group all value(except new line) upto last question mark in string(This will contain your value)
\? Match literally

//-------------------------select upto last ? -----------------------------

str = "https://localhost:8443/site/recipes/recepten-zoeken/menugang:hoofdgerecht/soort:italiaans/seizoen:winter?Nrpp=24";
var myRegexp = /\/recepten-zoeken\/(.*)\?/;
console.log(myRegexp.exec(str)[1]);

Capture upto first question mark

Try this regex \/recepten-zoeken\/([^?]*)\?.

Explanation:-

\/ Match forward slash
recepten-zoeken Match literally
\/ Match forward slash
([^?]*) Capture in a group all value(except ?) upto first question mark in string(This will contain your value)(here [^?] means match any character except ?)
\? Match literally

//-------------------------select upto first ? -----------------------------

var str = "https://localhost:8443/site/recipes/recepten-zoeken/menugang:hoofdgerecht/soort:italiaans/seizoen?:winter?Nrpp=24";
var myRegexp = /\/recepten-zoeken\/([^?]*)\?/;
console.log(myRegexp.exec(str)[1]);

回答2:

Try capturing your values in a capturing group:

recepten-zoeken\/([^?]+)\?

Explanation

recepten-zoeken Match literally
\/ Match forward slash
([^?]+) Capture in a group a negated character class [^ which will match NOT a question mark. (This will contain your value)
\? Match literally

var s = "https://localhost:8443/site/recipes/recepten-zoeken/menugang:hoofdgerecht/soort:italiaans/seizoen:winter?Nrpp=24"
console.log(s.match(/recepten-zoeken\/([^?]+)\?/)[1])

Credits to ctwheels for providing the snippet and comment.

回答3:

This would do it:

var match = url.match(/\/recepten-zoeken\/([^?]+)\?/);
// match[1] == "menugang:hoofdgerecht/soort:italiaans/seizoen:winter"

This regex will match the first occurrence of /recepten-zoeken/, then it will start capturing all characters that are not question marks ([^?] is a negative character class which matches anything not in the class).

Note that it will also ensure that there is a question mark. If you want to support cases where there is no question mark, then just remove the final \?.

Your original regular expression only matches a single character (the .), then it tries to look ahead for characters that are not c, e, k, / or between n and z.

来源：https://stackoverflow.com/questions/49881450/regex-that-wil-match-after-keyword-and-before-question-mark

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