问题
I am trying to specialize my function template for list of int pointers.
template <typename typ>
void sortowanie(typ *tablica, int rozmiar, Komparator<typ> *komparator)
{
int p;
for(int j = rozmiar - 1; j > 0; j--)
{
p = 1;
for(int i = 0; i < j; i++)
if(komparator->porownaj(tablica[i], tablica[i + 1]))
{
typ pom = tablica[i];
tablica[i] = tablica[i + 1];
tablica[i + 1] = pom;
p = 0;
}
if(p) break;
}
};
template<>
void sortowanie<int *>(int **tablica, int rozmiar, Komparator<int> *komparator)
{
int p;
for(int j = rozmiar - 1; j > 0; j--)
{
p = 1;
for(int i = 0; i < j; i++)
if(komparator->porownaj(*tablica[i], *tablica[i + 1]))
{
int *pom = tablica[i];
tablica[i] = tablica[i + 1];
tablica[i + 1] = pom;
p = 0;
}
if(p) break;
}
};
But I get the following errors:
obliczenia.cpp:43:10: error: template-id ‘sortowanie<int*>’ for ‘void obliczenia::sortowanie(int**, int, Komparator<int>*)’ does not match any template declaration
void sortowanie<int*>(int* * tablica, int rozmiar, Komparator<int> *komparator) {
^
obliczenia.cpp:43:10: error: template-id ‘sortowanie<int*>’ for ‘void obliczenia::sortowanie(int**, int, Komparator<int>*)’ does not match any template declaration
void sortowanie<int*>(int* * tablica, int rozmiar, Komparator<int> *komparator) {
回答1:
Perhaps this is a typo.
In the generic template version, you have:
template <typename typ>
void sortowanie(typ *tablica, int rozmiar, Komparator<typ> *komparator) {
In the specialization, you have:
template<>
void sortowanie<int*>(int* * tablica, int rozmiar, Komparator<int> *komparator) {
^^^^^^^^^^^^^^^^^^^^^^^^^^^
I suspect you mean that to be: Komparator<int*> *komparator.
Without that, the function can be an overload but it can't be a template specialization. In that case, you need to remove the template <> before the function declaration.
来源：https://stackoverflow.com/questions/29928891/function-template-specialization-error