How can we block Ruby on Rails on a Memcached read so it doesn't eat CPU?

问题

We have a daemon which scans a table for dirty bits and then schedules dirty rows to a delayed_job in batches. In order to avoid a constant select from data where dirty = 1, we set up a memcached barrier, which wraps the table scan, like

   loop do # daemon
     until Rails.cache.fetch("have_dirty_rows") do end
     page = 1
     loop do # paginate dirty rows
       dirty_batch = paginate(#:select     => "*",
                           :order      => "id",
                           :per_page   => DIRTY_GET_BATCH_SIZE,
                           :conditions => {:dirty => 1},
                           :page       => page)
       if dirty_batch.empty?
         Rails.cache.write("have_dirty_rows",false)
         break
       end
       ...
       page = page.next
     end
   end

Unless I add some sleep 0.0001 or such, the loop eats 100% CPU still. Is there an efficient mechanism in Ruby/Rails which will block on something like the memcached value, or which we can feed from a memcached value, so it's not polling all the time?

回答1:

Active polling is BAD ! Where are the dirty bits comin from? It woul be better if this process uses a message queue mechanism (eg RabbitMQ ) to notify other processes. That something has changed in the database.

来源：https://stackoverflow.com/questions/6714954/how-can-we-block-ruby-on-rails-on-a-memcached-read-so-it-doesnt-eat-cpu