问题
I need to remoe all leading zeros in a csv from all IP addresses, but not others (like hostnames).
I got the following, which does remove all
s/(?<!\d)0+(?=\d)//g
sample CSV:
192.168.001.000,any comment,host0003.zone.com
010.001.100.000,any long 000 string,host004.zone.com
should become
192.168.1.0,any comment,host0003.zone.com
10.1.100.0,any long 000 string,host004.zone.com
Any ideas?
回答1:
Try Regexp::Common and Net::IP if you don't mind using CPAN modules.
$ <sample.csv perl -MRegexp::Common -MNet::IP -ple 's/($RE{net}{IPv4})/Net::IP->new($1)->ip/ge'
回答2:
Try this:
use strict;
use warnings;
use Data::Dumper;
for (<DATA>) {
   print join(",",map{ if($_=~/^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$/s){$_=~s/^0*(\d+)/$1/sg;$_=~s/^0*?\./0/sg;$_=~s/\.0+(\d+)/\.$1/sg;$_;}else{$_} } split /,/is,$_);
}
__DATA__
192.168.001.000,any comment,host0003.zone.com
010.001.100.000,any long 000 string,host004.zone.com
回答3:
This works for your example data:
use strict;
use warnings;
while(my $line = <DATA>) {
    $line =~ s/(?:^|\.)0+(?=\d)//g;
    print $line;
}
__DATA__
192.168.001.000,any comment,host0003.zone.com
010.001.100.000,any long 000 string,host004.zone.com
prints:
192.168.1.0,any comment,host0003.zone.com
10.1.100.0,any long 000 string,host004.zone.com
In any case, I strongly recommend that you use a CPAN module to parse the CSV file, like Text::CSV.
回答4:
The unix regex below may help:
',\{0,2\}\([0][0-9]\{2\}\.\)\([0-9]\{3\}\.\)\{2\}'.
来源:https://stackoverflow.com/questions/24949991/remove-leading-zeros-only-in-ip-addresses