I am in the process of making a jquery application to hide an image after a specified interval of time by using setInterval(). The problem is that the hide image function executes immediately without delay.
$(document).ready(function() {
setInterval(change(), 99999999);
function change() {
$('#slideshow img').eq(0).removeClass('show');
}
});
I am testing it in jsfiddle.
You called the function immediately instead of passing it to setInterval.
setInterval( change, 1500 ) - passes function change to setInterval
setInterval( change(), 1500 ) - calls the function change and passes the result (undefined) to setInterval
Where you have setInterval(change(), 99999999); you end up calling the change() function immediately and passing the return value of it to the setInterval() function. You need delay the execution of change() by wrapping it in a function.
setInterval(function() { change() }, 9999999);
Or you can delay it by passing setInterval() just the function itself without calling it.
setInterval(change, 9999999);
Either works. I personally find the first one a bit clearer about the intent than the second.
You have setInterval(change(), 99999999); and it should be setInterval(change, 99999999);. See the documentation of setInterval/setTimeout why. :)
Common mistake, happens to me all the time. :)
Change setInterval(change(), 99999999); to setInterval(change, 99999999);
And 99999999 means 99999999 milliseconds as you known.
来源:https://stackoverflow.com/questions/7858262/function-in-setinterval-executes-without-delay