问题
Possible Duplicate:
pass php variable value to javascript
I have a piece of php code
function formLetterTabPage($redirect_url, $letter){
  $test = 123;
  foreach (range('A','Z') as $val) {
    if($val == $letter){
        echo '<li class="a" id="li_'.$letter.'" onclick="tab_click('.$letter.')">'.$letter.'</li>';
    }else{
        echo '<li class="b" id="li_'.$val.'" onclick="tab_click('.$letter.')">'.$val.'</li>';
    }
  }
}
and my javascript function tab_click is quite simple:
function tab_click(f){
  alert(f);
}
the key part is here:
echo '<li class="a" onclick="tab_click('.$letter.')">'.$letter.'</li>';
it cannot work out ! so I change it like this:
$test = 123;
echo '<li class="a" onclick="tab_click('.$test .')">'.$letter.'</li>';
it works perfert, and the page show me 123! I wonder why this happen? And I checked the html code, it ok:
<li class="navi_letter_leftb" id="li_A" onclick="tab_click(A)">A</li>
ok, I don't know why?
回答1:
You need additional quotes in your javascript for string parameters:
echo '<li class="a" onclick="tab_click(\''.$letter.'\')">'.$letter.'</li>';
In your test case $test = 123; you are passing an integer, so the quotes are not needed.
EDIT
Output without quotes (invalid javascript):
<li class="a" onclick="tab_click(a)">a</li>
Output with quotes:
<li class="a" onclick="tab_click('a')">a</li>
    回答2:
If you pass $test = 123 your javascript it's working because you're passing an integer value.
But your $letter it's a string and so the resulting html code it's wrong:
<li class="navi_letter_leftb" id="li_A" onclick="tab_click(A)">A</li>
You have to wrap your string between quotes ''. So it should be:
<li class="navi_letter_leftb" id="li_A" onclick="tab_click('A')">A</li>
and you should change your code to:
echo '<li class="a" onclick="tab_click(\''.$letter.'\')">'.$letter.'</li>';
    来源:https://stackoverflow.com/questions/12822686/how-to-pass-php-parameter-to-javascript