(N叉树 递归) leetcode589. N-ary Tree Preorder Traversal

Given an n-ary tree, return the preorder traversal of its nodes' values.

For example, given a 3-ary tree:

 

 

Return its preorder traversal as: [1,3,5,6,2,4].

 

Note:

Recursive solution is trivial, could you do it iteratively?

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额，这个迭代不会，不过，如果会了二叉树的前序遍历的递归解法的话，解这个题就会感觉简单了，同理，后序遍历也是，不过，中序遍历上可能会很难写。

C++代码：

/*
// Definition for a Node.
class Node {
public:
    int val;
    vector<Node*> children;

    Node() {}

    Node(int _val, vector<Node*> _children) {
        val = _val;
        children = _children;
    }
};
*/
class Solution {
public:
    vector<int> preorder(Node* root) {
        vector<int> res;
        helper(root,res);
        return res;
    }
    void helper(Node *root,vector<int> &res){
        if(!root) return;
        res.push_back(root->val);
        for(Node* cur : root->children){
            helper(cur,res);
        }
    }
};

 

来源：https://www.cnblogs.com/Weixu-Liu/p/10776096.html