问题
I don't understand why the following code doesn't compile:
#include <iostream>
class Test {
public:
Test() {
std::cout << "Constructor" << std::endl;
}
Test(const Test&) {
std::cout << "Copy Constructor" << std::endl;
}
Test& operator=(const Test&) {
std::cout << "Assign Op" << std::endl;
return *this;
}
Test& operator=(const volatile Test&) {
std::cout << "Volatile Assign Op" << std::endl;
return *this;
}
};
volatile Test func() {
Test a;
return a;
}
int main() {
Test b;
volatile Test c;
b = c; // this line is correct
b = func(); // this line doesnt compile correct
return 0;
}
the line:
b = c; // this line is correct
While:
b = func(); // this line doesn t compile
The compile complains about:
test.cc: In function ‘int main()’:
test.cc:31:14: error: no match for ‘operator=’ in ‘b = func()()’
test.cc:31:14: note: candidates are:
test.cc:12:11: note: Test& Test::operator=(const Test&)
test.cc:12:11: note: no known conversion for argument 1 from ‘volatile Test’ to ‘const Test&’
test.cc:17:11: note: Test& Test::operator=(const volatile Test&)
test.cc:17:11: note: no known conversion for argument 1 from ‘volatile Test’ to ‘const volatile Test&’
In the beginning I thought that it was due to constructor elision, which I was experimenting how to disable it using volatile, when I got into this situation. Compiling with:
-fno-elide-constructors
Didn't make any difference.
Any explanation for this? Testing with:
g++ (GCC) 4.6.3 20120306 (Red Hat 4.6.3-2)
回答1:
Per [dcl.init.ref]/5, for a reference (i.e. the parameter of Test::operator=()) to be initialized by binding to an rvalue, the reference must be a const non-volatile lvalue reference, or an rvalue reference:
— Otherwise, the reference shall be an lvalue reference to a non-volatile const type (i.e., cv1 shall be
const), or the reference shall be an rvalue reference.
The line b = c; works because you are binding a reference (the parameter of Test::operator=()) to an lvalue.
来源:https://stackoverflow.com/questions/28048208/assigning-a-volatile-rvalue