问题
Is it possible to output stdout to file, but ignore stderr?
I have a Python script that uses sys.stderr.write(error) to output errors to stderr. I'd like to ignore these for this particular script. How is this possible?
Here is the current entry in the crontab:
* * * * * /Users/me/bin/scrape-headlines /Users/me/proxies.txt >> /Users/me/headlines.txt 2>&1
scrape-headlines is a bash script that calls the Python script.
回答1:
The 2>&1 redirects stderr to stdout, appending it to the headlines.txt.
So, redirect stderr to /dev/null:
* * * * * /Users/me/bin/scrape-headlines /Users/me/proxies.txt >> /Users/me/headlines.txt 2> /dev/null
回答2:
You can use the "2" descriptor to control stderr separately and, e.g., redirect it to /dev/null:
* * * * * /Users/me/bin/scrape-headlines /Users/me/proxies.txt >> /Users/me/headlines.txt 2>/dev/null
回答3:
You can redirect stderr and stdout separately.
$ command 1> /some/file 2> /some/other/file
If you want to drop stderr, send it to/dev/null.
来源：https://stackoverflow.com/questions/35522894/cronjob-how-to-output-stdout-and-ignore-stderr