PHP output only one value in for each

问题

I'm having trouble with output in for each function in PHP (actually don't know how to set the code to do what I need). I'd like to output some text if every item in foreach is equal to some value. If I put

foreach($items as $item) {
    if($item == 0){ echo "true"; }
}

I will get true for every item and I need to output true only if all items are equal to some value.

Thanks!

回答1:

This peice of code work for most type of variables. See how it works in inline comment.

 $count=0; // variable to count the matched words
 foreach ($items as $item)
   {
     if($item == $somevalue)
       {
         $count++; // if any item match, count is plus by 1
       }
   }
 if($count == count($items))
   {
     echo "true"; // if numbers of matched words are equal to the number of items
   }
 else
  {
    echo "false";
  }

Hope it works , And sorry for any mistake

回答2:

This is most likely due to PHP type juggling your values. Your values are probably not numeric so when you do a loose comparison (==) PHP converts them to integers. Strings that do not start with digits will become zero and your statement will be true.

To fix this use the === comparison operator. This will compare value and type. So unless a value is the integer zero it will be false.

if($item === 0){ echo "true"; }

If you are trying to see if all items are equal to some value this code will do this for you:

$equals = 0;
$filtered = array_filter($items, function ($var) use ($equals) {
    return $var === $equals;
});
if (count(count($items) === count($filtered)) {
    echo "true";
}

回答3:

$ok = true;
foreach ($items as $item) 
{
    if ($item != 0)
    { 
        $ok = false;
    }
}
if ( $ok == true)
{
    echo 'true';
}

回答4:

$bool = 0;
foreach($items as $item) {
    if($item == $unwantedValue)
    { $bool=1; break; }
}

if($bool==0)
echo 'true';

回答5:

$equals=true;

foreach($items as $item) {
    if($item!=0)
    {
        $equals=false;
        break;
    }
}
if($equals) {
    echo 'true';
}

回答6:

if you want to check the values is same with some value in variabel and print it use this

<?php 
$target_check = 7;

$items = array(1, 4, 7, 10, 11);

foreach ($items as $key => $value) {
    if ($value == 7) echo "the value you want is exist in index array of " . $key . '. <br> you can print this value use <br><br> echo $items[' . $key . '];';
}


?>

but if you just want to check the value is exist in array you can use in_array function.

<?php

$target_check = 2;

if (in_array($target_check, $items)) echo "value " . $target_check . 'found in $items';
else echo 'sorry... ' . $target_check . ' is not a part of of $items.';
?>

回答7:

<?
$items=array(0,1,2,0,3,4);
foreach($items as $item) {
    if($item == 0){ echo "true"; }
}
?>

your code work! check the source of the $items array

来源：https://stackoverflow.com/questions/23270686/php-output-only-one-value-in-for-each

标签

php

if-statement

foreach

output