javascript setTimeout() first argument: expression error

问题

function Timer() {
 this.initialTime = 0;
 this.timeStart = null;

 this.getTotalTime = function() {
  timeEnd = new Date();
  diff = timeEnd.getTime() - this.timeStart.getTime();

  return diff+this.initialTime;
 };

 this.formatTime = function() {
  interval = new Date(this.getTotalTime());

  return  interval.getHours() + ":" +  interval.getMinutes() + ":" + interval.getSeconds();
 };

 this.start = function() {
  this.timeStart = new Date();

  setTimeout("this.updateTime()", 1000);
 };

 this.updateTime = function() {
  alert(this.formatTime());
  setTimeout("this.updateTime()", 1000);
 };
}


timer = new Timer();
timer.start();

I am getting an error:

this.updateTime is not a function

Any ideas?

Thanks

回答1:

Your string is not evaluated in the context of your object, so this doesn't refer to what you think it does.

You should not be passing a string argument to setTimeout. Instead, you should pass an anonymous function that calls your method with a saved copy of this.

For example:

var self = this;
setTimeout(function() { self.updateTime(); }, 1000);

The self variable is necessary because setTimeout's callback is also not evaluated in the context of your object.

回答2:

try

var me = this;
setTimeout(function() { me.updateTime() }, 1000);

回答3:

is there a more elegant way?

Yes, in ECMAScript Fifth Edition:

setTimeout(this.updateTime.bind(this), 1000);

However, until all browsers support Fifth Edition (which they don't yet by a long measure), you should add your own implementation of Function.bind as fallback. eg.:

// Add ECMA262-5 method binding if not supported natively
//
if (!('bind' in Function.prototype)) {
    Function.prototype.bind= function(owner) {
        var that= this;
        if (arguments.length<=1) {
            return function() {
                return that.apply(owner, arguments);
            };
        } else {
            var args= Array.prototype.slice.call(arguments, 1);
            return function() {
                return that.apply(owner, arguments.length===0? args : args.concat(Array.prototype.slice.call(arguments)));
            };
        }
    };
}

You might also prefer to use setInterval to avoid the repeated setTimeout calls. Finally, you should remember to declare all your variables (timeEnd, diff, etc.) as var, otherwise you're getting accidental globals, which can cause you horrible debugging heartache.

回答4:

If you supply a string to setTimeout, this string will be executed literally. The thing is, it will be executed sometime later in the global context, outside your Timer object, so this means something completely different.

Just pass the function itself like so:

function Timer() {
  var self = this;   // make reference to this that won't change with context

  this.updateTime = function() {
    alert(self.formatTime());
    setTimeout(self.updateTime, 1000);
  };

}

来源：https://stackoverflow.com/questions/2604597/javascript-settimeout-first-argument-expression-error

标签

javascript

time

settimeout