问题
Here is the function calc.lua:
function foo(n)
return n*2
end
Here is my LuaJavaCall
L.getGlobal("foo");
L.pushJavaObject(8);
int retCode=L.pcall(1,1,0); // nResults)//L.pcall(1, 1,-2);
String errstr = L.toString(-1); // Attempt to perform arithmetic on local variable 'n'
Update: as indicated below I needed to use L.pushNumber(8.0) instead of L.pushJavaObject()
回答1:
Try using L.pushNumber
instead of L.pushJavaObject
like this:
L.getGlobal("foo");
L.pushNumber(8.0);
int retCode = L.pcall(1,1,0);
String errstr = L.toString(-1);
Lua probably sees JavaObject as a type of 'userdata' in which case there are no predefined operations for it; Lua won't know what to do with a JavaObject * 2
since you didn't define how to handle it.
OTOH, Lua does know how to handle a number since that's a builtin primitive type. For the code snippet you presented, pushing a number would be the least painful way to get it working instead of writing extra code that tells Lua how to work with numbers wrapped inside a JavaObject.
来源:https://stackoverflow.com/questions/8622409/lua-error-attempt-to-perform-arithmetic-on-local-variable