问题
I've never asked any question here before, but after spending many hours searching for a hint I decided to ask a question.
I have a project at school where I need to create a table from DB for all records for one user, and then create an expanded view for all details for a chosen record.
So far I have:
$user = 'myuser';
$pass = 'mypassword';
$db = new PDO( 'mysql:host=localhost;dbname=mydb', $user, $pass );
$sql = "
SELECT id,login
FROM quotes_taxi
WHERE login='[usr_login]'";
$query = $db->prepare( $sql );
$query->execute();
$results
where 'id' is obviously ID for each record. Then I create a table using FOREACH
<?php foreach( $results as $row ){
echo '<tr>';
echo '<td>'; echo $row['id']; echo '</td>';
echo '<td>'; echo $row['login']; echo '</td>';
echo '<td>'; echo '<a href="../view/index.php?id=$row['id']"> View All </a>';
echo '</td>';
echo "</tr>";
}
?>
the problem I am having is: how can I attached that 'id' within the link (and it needs to be a separate button for each ID), so I can pass it to the view/index.php where I am using
$quote_id = $_GET["id"];
to get all other details of a chosen ID...
I know I have an error in that line, I just cannot figure it what. I also assume it is an easy problem, but I just cannot get my head around it
any help is most appreciated. Thank you
回答1:
Try to separate your PHP and HTML that way it will be easier to find errors quickly. Try the following code.
<table>
<tr>
<th>Id</th>
<th>Login</th>
<th>View</th>
</tr>
<?php foreach ($results as $row) : ?>
<tr>
<td><?php echo $row['id']; ?></td>
<td><?php echo $row['login']; ?></td>
<td><a href="../view/index.php?id=<?php echo $row['id']; ?>"> View All </a></td>
</tr>
<?php endforeach; ?>
</table>
Output
来源:https://stackoverflow.com/questions/43957714/php-post-value-from-foreach-to-another-page