Match a regex and reverse the matches within the target string

问题

Based on this question Regex \d+(?:-\d+)+ will match this 10-3-1 and 5-0.

Example:

This is 10-3-1 my string

After performing the matching and reversing, I want it to be like this:

This is 1-3-10 my string

Notice that 10-3-1 should become 1-3-10 and not normal string reverse which would result in 1-3-01.

回答1:

A basic algorithm would be:

1. Extract the match from the string. "10-3-1"
2. Split the match into a segments by the "-" character.
3. You now have a list of elements. ["10","3","1"]
4. Reverse the list. ["1","3","10"]
5. Join the elements of the array with the "-" character. "1-3-10"
6. Replace the match with newly joined string.

回答2:

Although the question was answered here is a piece of code with a slightly modified regex:

var text = "This is 10-3-1 and 5-2.";
var re = new Regex(@"((?<first>\d+)(?:-(?<parts>\d+))+)");
foreach (Match match in re.Matches(text))
{
    var reverseSequence = match
                            .Groups["first"]
                            .Captures.Cast<Capture>()
                            .Concat(match.Groups["parts"].Captures.Cast<Capture>())
                            .Select(x => x.Value)
                            .Reverse()
                            .ToArray();
    text = text.Replace(match.Value, string.Join("-", reverseSequence));
}

来源：https://stackoverflow.com/questions/6619398/match-a-regex-and-reverse-the-matches-within-the-target-string